\(\theta=90^{\circ}, \sin \theta=1, \mathrm{v}=6 \times 10^{7} \,\mathrm{m} / \mathrm{s}\)
\(\frac{\mathrm{e}}{\mathrm{m}}=1.7 \times 10^{11} \,\mathrm{C} / \mathrm{kg}\)
\(\mathrm{r}=\frac{\mathrm{mv}}{\mathrm{Be}}=\frac{6 \times 10^{7}}{1.5 \times 10^{-2} \times 1.7 \times 10^{11}}\)
\(=2.35 \times 10^{-2}\, \mathrm{m}=2.35\, \mathrm{cm}\)