MCQ
In a compound the ratio of masses of $H,C,O$ and $N$ is $1:3:4:7$. The empirical formula is
- A$HC_3O_4N_7$
- ✓$H_4CON_2$
- C$HC_4O_2N_2$
- DNone of these
✓
Answer
Correct option: B.
$H_4CON_2$
b
$\mathrm{H}=1 / 1=1=4 \quad \therefore \mathrm{H}_{4} \mathrm{CON}_{2}$
$\mathrm{H}=1 / 1=1=4 \quad \therefore \mathrm{H}_{4} \mathrm{CON}_{2}$
$C=3 / 12=\frac{1}{4}=1$
$\mathrm{O}=4 / 16=\frac{1}{4}=1$
$\mathrm{N}=7 / 14=\frac{1}{2}=2$
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