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11. thermodynamics — Physics STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 SciencePhysics11. thermodynamics1 Mark
MCQ
In a heat engine, the temperature of the source and sink are $500\, K$ and $375\, K$. If the engine consumes $25\times10^5\, J$ per cycle, the work done per cycle is
  • ✓
    $6.25\times10^5\, J$
  • B
    $3\times10^5\, J$
  • C
    $2.19\times10^5\, J$
  • D
    $4\times10^4\, J$
✓

Answer

Correct option: A.
$6.25\times10^5\, J$
a
Here, $T_{1}=500 \mathrm{K}, T_{2}=375 \mathrm{K}$

$\mathrm{Q}_{1}=25 \times 10^{5} \mathrm{J}$

$\therefore \eta=1-\frac{\mathrm{T}_{2}}{\mathrm{T}_{1}}=1-\frac{375}{500}=0.25$

$\mathrm{W}=\eta \mathrm{Q}=0.25 \times 25 \times 10^{5}=6.25 \times 10^{5} \mathrm{J}$

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