In a parallel plate condenser, the radius of each circular plate is $12\,cm$ and the distance between the plates is $5\,mm$. There is a glass slab of $3\,mm$ thick and of radius $12\,cm$ with dielectric constant $6$ between its plates. The capacity of the condenser will be
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(c) $C = \frac{{{\varepsilon _0}A}}{{d - t + \frac{t}{K}}} = \frac{1}{{4\pi \times 9 \times {{10}^9}}}.\frac{{\pi \,{{(0.12)}^2}}}{{\left( {2 + \frac{1}{2}} \right)\,{{10}^{ - 3}}}}$
$ = \frac{{2 \times 144 \times {{10}^{ - 10}}}}{{36 \times 5}} = 160\,pF$
$ = \frac{{2 \times 144 \times {{10}^{ - 10}}}}{{36 \times 5}} = 160\,pF$
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