In a steady state of thermal conduction, temperature of the ends $A$ and $B$ of a $20\, cm$ long rod are ${100^o}C$ and ${0^o}C$ respectively. What will be the temperature of the rod at a point at a distance of $6$ cm from the end $A$ of the rod....... $^oC$
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(b) In steady state, temperature gradient = constant

==> $\frac{{({\theta _A} - {\theta _x})}}{6} = \frac{{({\theta _A} - {\theta _B})}}{{20}}$==> $(100 -\theta_x)$ $ = \frac{6}{{20}} \times (100 - 0)$

==> ${\theta _x} = 70^\circ C$

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