==> $\frac{{({\theta _A} - {\theta _x})}}{6} = \frac{{({\theta _A} - {\theta _B})}}{{20}}$==> $(100 -\theta_x)$ $ = \frac{6}{{20}} \times (100 - 0)$
==> ${\theta _x} = 70^\circ C$

Then, for the arrangement as shown in the figure. The value of temperature $T$ of the steel - copper junction in the steady state will be ........... $^{\circ} C$
