In a thermodynamics process, pressure of a fixed mass of a gas is changed in such a manner that the gas releases $20 J$ of heat and $8J$ of work is done on the gas. If the initial internal energy of the gas was $30J.$ The final internal energy will be ...... $J$
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(a)Given $\Delta Q = - 20J,$ $\Delta W = - 8J$and ${U_1} = 30J$
$\Delta Q = \Delta U + \Delta W$==> $\Delta U = (\Delta Q - \Delta W)$
==> $({U_f} - {U_i})$= $({U_f} - 30) = - 20 - ( - 8)$ ==>${U_f} = 18J$
$\Delta Q = \Delta U + \Delta W$==> $\Delta U = (\Delta Q - \Delta W)$
==> $({U_f} - {U_i})$= $({U_f} - 30) = - 20 - ( - 8)$ ==>${U_f} = 18J$
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