In a Wheatstone's bridge, three resistances $P, Q$ and $R$ connected in the three arms and the fourth arm is formed by two resistances $S_1$ and $S_2$ connected in parallel. The condition for the bridge to be balanced will be
AIEEE 2006, Medium
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$\frac{P}{Q}=\frac{R}{S} \text { where } S=\frac{S_{1} S_{2}}{S_{1}+S_{2}}$
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