In the following circuit, the battery has an emf of $2\mathrm{V}$ and an internal resistance of $\frac{2}{3}\ \Omega$. The power consumption in the entire circuit is$..... W.$
JEE MAIN 2024, Diffcult
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$\mathrm{R}_{\text {eq }}=\frac{4}{3} \Omega$
$\therefore \mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}_{\text {eq }}}=\frac{4}{4 / 3}=3 \mathrm{~W}$
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