In an adiabatic process, the density of a diatomic gas becomes $32$ times its initial value. The final pressure of the gas is found to be $n$ times the initial pressure. The value of $n$ is
A$326$
B$\frac{1}{32}$
C$32$
D$128$
JEE MAIN 2020, Medium
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D$128$
d In adiabatic process
$PV ^{\gamma}= constant$
$P \left(\frac{ m }{\rho}\right)^{\gamma}= constant$
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