Three capacitors are connected to $D.C.$ source of $100\;volts$ shown in the adjoining figure. If the charge accumulated on plates of ${C_1},\;{C_2}$ and ${C_3}$ are ${q_a},\;{q_b},\;{q_c},{q_d}.{q_e}$ and ${q_f}$ respectively, then
A${q_b} + {q_d} + {q_f} = \frac{{100}}{9}\,C$
B${q_b} + {q_d} + {q_f} = 0$
C${q_a} + {q_c} + {q_e} = 50\,C$
D${q_b} = {q_d} = {q_f}$
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D${q_b} = {q_d} = {q_f}$
d (d) In series combination, charge is same on each capacitor.
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