In an $RC$ circuit while charging, the graph of in $i$ versus time is as shown by the dotted line in the diagram figure, where $i$ is the current. When the value of the resistance is doubled, which of the solid curve best represents the variation of in $i$ versus time
IIT 2004, Medium
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(b) In case of $RC$ circuit $i = \frac{E}{R}{e^{ - t/RC}}$
${\log _e}i = - \frac{t}{{RC}} + {\log _e}\frac{E}{R}$
When $R$ is doubled, the slope of the curve increases. Further at $t = 0$, the current will be less for an increased value of resistance.
${\log _e}i = - \frac{t}{{RC}} + {\log _e}\frac{E}{R}$
When $R$ is doubled, the slope of the curve increases. Further at $t = 0$, the current will be less for an increased value of resistance.
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