Two batteries and two condensers are connected as shown in the figure. The charge on $2\,\mu F$ capacitor is.....$\mu F$
Medium
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Net $P . d=18-13=5 V$
$\mathrm{C}_{\mathrm{eq}}=\frac{3 \times 2}{3+2}=\frac{6}{5} \mu \mathrm{F} \quad \mathrm{Q}=\mathrm{CV}=6 \mu \mathrm{C}$
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