In Dumas' method for estimation of nitrogen, 0.5 gram of an organ… - Vidyadip

MCQ

In Dumas' method for estimation of nitrogen, 0.5 gram of an organic compound gave 60 mL of nitrogen collected at 300 K temperature and 715 mm Hg pressure. The percentage composition of nitrogen in the compound (Aqueous tension at $300 \mathrm{~K}=15 \mathrm{~mm} \mathrm{Hg}$ ) is

A
1.257
B
20.87
C
18.67
D
12.57

✓

Answer

D. 12.57
Pressure of $\mathrm{N}_{2}$ gas $=(715-15)$
$=700 \mathrm{mmHg}$
$\mathrm{n}_{\mathrm{N}_{2}}=\frac{\mathrm{PV}}{\mathrm{RT}}$
$\mathrm{n}_{\mathrm{N}_{2}}=\frac{700 \times 60 \times 10^{-3}}{760 \times 0.0821 \times 300}$
$\begin{aligned}=2.24 & \times 10^{-3} mol \\ \text { Mass of } N _2 & =2.24 \times 10^3 \times 28 g \\ & =0.06272 g\end{aligned}$
$\% \mathrm{~N}_{2}=\frac{0.06272}{0.5} \times 100 \simeq 12.57$

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