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Semiconductor Electronic: Material, Devices And Simple Circuits — Physics STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 SciencePhysicsSemiconductor Electronic: Material, Devices And Simple Circuits1 Mark
MCQ
In Fig., assuming the diodes to be ideal:

  • A
    D1 is forward biased and D2 is reverse biased and hence current flows from A to B.
  • B
    D2 is forward biased and D1 is reverse biased and hence no current flows from B to A and vice versa.
  • C
    D1 and D2 are both forward biased and hence current flows from A to B.
  • D
    D1 and D2 are both reverse biased and hence no current flows from A to B and vice versa.
✓

Answer

  1. D2 is forward biased and D1 is reverse biased and hence no current flows from B to A and vice versa.

Solution:

A symbol of the diode is represented like this: In this problem first we have to check the polarity of the diodes. -10 is the lower voltage in the circuit. Now p-side of p-n juction D1 is connected to lower voltage and n-side of D1 to higher voltage. Thus D1 is reverse biased. Now, let us analyse 2nd diode of the given circuit. The p-side of p-n junction D1 is at higher potential and n-side of D2 is at lower potential. Therefore D2 is forward biased.

Hence, current flows through the jucntion from B to A.

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