Question
In figure, $AB = AC$ and $\angle\text{ACD} = 115^\circ.$ Find $\angle\text{A}?$
✓
Answer
$C = 180^\circ - 115^\circ $
$= 65^\circ AB = AC$ And hence
$\angle\text{B} =\angle\text{C} = 65^\circ.$
Then $A = 180^\circ$
$ - 2 \times 65^\circ $
$= 50^\circ$
$= 65^\circ AB = AC$ And hence
$\angle\text{B} =\angle\text{C} = 65^\circ.$
Then $A = 180^\circ$
$ - 2 \times 65^\circ $
$= 50^\circ$
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