Question
In figure, $\angle\text{AOC}$ and $\angle\text{BOC}$ from a linear pair. If $a - 2b = 30°$, find $a$ and $b.$ 
✓
Answer
Given that, $\angle AOC$ and $\angle BOC$ form a linear pair If $a - b =30 \angle AOC = a ^{\circ}, \angle BOC = b ^{\circ}$ Therefore, $a + b =180 \ldots$
$(i)$ Given $a -2 b=30$
..$(ii)$ By subtracting
$(i)$ and
$(ii)$
$a+b-a+2 b=180-303 b=150 b=\frac{150}{3} b=50$ Since $a-2 b=$
$30 a-2$(50)$=30 a=30+100 a=130$
Hence, the values of $a$ and $b$ are $130^{\circ}$ and $50^{\circ}$ respectively.
$(i)$ Given $a -2 b=30$
..$(ii)$ By subtracting
$(i)$ and
$(ii)$
$a+b-a+2 b=180-303 b=150 b=\frac{150}{3} b=50$ Since $a-2 b=$
$30 a-2$(50)$=30 a=30+100 a=130$
Hence, the values of $a$ and $b$ are $130^{\circ}$ and $50^{\circ}$ respectively.
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