In the adjoining circuit, the e.m.f. of the cell is 2, volt and the internal resistance is negligible. The resistance of the voltmeter is 80

Q: In the adjoining circuit, the $e.m.f.$ of the cell is $2\, volt$ and the internal resistance is negligible. The resistance of the voltmeter is $80 \,ohm$. The reading of the voltmeter will be ............. $volt$

c (c) Total resistance of the circuit $ = \frac{{80}}{2} + 20 = 60\,\Omega $ $ \Rightarrow $ Main current $i = \frac{2}{{60}} = \frac{1}{{30}}A$ Combination of voltmeter and $80$ $\Omega$ resistance is connected in series with $20$ $\Omega$, so current through $20$ $\Omega$ and this combination will be same $ = \frac{1}{{30}}A$. Since the resistance of voltmeter is also $80$ $\Omega$, so this current is equally distributed in $80$ $\Omega$ resistance and voltmeter (i.e.$\frac{1}{{60}}A$ through each) $P.D.$ across $80$ $\Omega$ resistance $ = \frac{1}{{60}} \times 80 = 1.33\,V$

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

In the adjoining circuit, the $e.m.f.$ of the cell is $2\, volt$ and the internal resistance is negligible. The resistance of the voltmeter is $80 \,ohm$. The reading of the voltmeter will be ............. $volt$

A$0.80$
B$1.60$
C$1.33$
D$2$

Medium

STD 11 Science
JEE
STD 12 - 3. current electricity
Physics

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