In the circuit shown below, the voltmeter reads $10V.$
  1. What is the combined resistance?
  2. What current flows?
  3. What is the p.d. across $ 2 Ω$ resistor?
  4. What is the p.d. across $3 Ω$ resistor?
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$I = 6V$
$\text{R}_1=2\Omega,\text{R}_2=3\Omega$
Combined resistance, $R_{tot} = 2 + 3 = 5$
$\text{I}=\frac{\text{V}}{\text{R}_\text{tot}}=\frac{10}{5}=2\text{A}$
p.d. across $2\Omega$ resistor $= I \times R_1 = 2 \times 2 = 4V.$
p.d. across $3\Omega$ resistor $= I \times R_2 = 2 \times 3 = 6V.$
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