When a current of $4.0A$ passes through a certain resistor for $10$ minutes,$ 2.88 \times 10J$ of heat are produced. Calculate:
- The power of the resistor.
- The voltage across the resistor.
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Given$: I = 4$ amp, $t = 10$min $= 10 \times 60 = 600 $sec, $H = 2.88 \times 10^4J$
$28800 = 4^2 \times R \times 600$
$R = 3$ ohm
We know that
$P = I^2\times R$
$= 4^2 \times 3$
$P = 48W$
$V = IR$
$V = 4 \times 3$
$V = 12V$
- We have
$28800 = 4^2 \times R \times 600$
$R = 3$ ohm
We know that
$P = I^2\times R$
$= 4^2 \times 3$
$P = 48W$
- $V = ?$
$V = IR$
$V = 4 \times 3$
$V = 12V$
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