In the whole cycle of the system, the loss of any type of heat energy should be zero
B
That the process should be too fast
C
That the process should be slow so that the working substance should remain in thermal and mechanical equilibrium with the surroundings
D
The loss of energy should be zero and it should be quasistatic
Medium
Download our app for free and get started
D
The loss of energy should be zero and it should be quasistatic
d (d) For a reversible process $\int {\frac{{dQ}}{T} = 0} $
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
$n-$ $moles$ of an ideal gas with constant volume heat capacity $C_v$ undergo an isobaric expansion by certain volume. The ratio of the work done in the process, to the heat supplied is
$Assertion :$ In adiabatic compression, the internal energy and temperature of the system get decreased.
$Reason :$ The adiabatic compression is a slow process.
Two different adiabatic paths for the same gas intersect two isothermal curves as shown in$P-V$ diagram. The relation between the ratio $\frac{V_a}{V_d}$ and the ratio $\frac{V_b}{V_c}$ is:
A Carnot engine working between $300\,K$ and $600\,K$ has work output of $800\, J$ per cycle. What is amount of heat energy supplied to the engine from source per cycle...... $J/cycle$
An ideal gas follows a process described by the equation $PV ^2= C$ from the initial $\left( P _1, V _1, T _1\right)$ to final $\left(P_2, V_2, T_2\right)$ thermodynamics states, where $C$ is a constant. Then