MCQ
In the circuit initially switch $S$ is open the $S$ is closed at $t = 0$ the difference between the maximum and minimum current that can flow in the circuit is.....$Amp$
- A$2$
- B$3$
- ✓$1$
- DNothing can be concluded
✓
Answer
Correct option: C.
$1$
c
Just after $\mathrm{S}$ is closed $\mathrm{i}=\frac{10}{10}=1$ $\mathrm{amp}$
Just after $\mathrm{S}$ is closed $\mathrm{i}=\frac{10}{10}=1$ $\mathrm{amp}$
Long after $\mathrm{S}$ is closed $= \mathrm{i}=\frac{10}{5}=2 \mathrm{\,amp}$
difference $=1$ $\mathrm{amp}$
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