In the circuit shown in figure, four capacitors are connected to a battery. A parallel plate capacitor has an electric field of $10^5\ V/m$ between the plates. If the charge on the capacitor plate is $1\  \mu C$, then the force on each capacitor plate is.....$Nt$
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Force of attraction between capacitor plate is $F=\frac{Q^{2}}{2 \epsilon_{o} A}=1 / 2 Q E$

putting values $F=0.5 \times 10^{-6} \times 10^{5}=0.05 N$

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