In the circuit shown, the thermal power dissipated in $R_1$ is $P$. The thermal power dissipated in $R_2$ is
A$P$
B$\frac{4 P}{9}$
C$\frac{2 P}{3}$
D$\frac{P}{9}$
Medium
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B$\frac{4 P}{9}$
b (b)
$P=i^2 R$
$P_2=\frac{4 i^2}{9} R=\frac{4 P}{9}$
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