MCQ
In the circuit, the potential difference across $PQ$ will be nearest to .............. $V$
- A$9.6$
- B$6.6$
- C$4.8$
- ✓$3.2 $
✓
Answer
Correct option: D.
$3.2 $
d
Potential difference across $PQ$ i.e. p.d. across the resistance of $20$
Potential difference across $PQ$ i.e. p.d. across the resistance of $20$
$\Omega$, which is $V = i × 20$ and $i = \frac{{48}}{{(100 + 100 + 80 + 20)}} = 0.16\,A$
$V = 0.16 \times 20 = 3.2\,V$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Two identical circular loops of metal wire are lying on a table without touching each other. $Loop- \,A$ carries a current which increases with time. In response, the $loop-\,B$
→Which of the following statements is false?
An electron moves along the line AB, which lies in the same plane as a circular loop of conducting wires as shown in the diagram. What will be the direction of current induced if any, in the loop
A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will:
The de-Broglie wavelength associated with the particle of mass $m$ moving with velocity $v$ is
→In a Young’s double slit experiment, the source illuminating the slits is changed from blue to violet. The width of the fringes
A steady current of 5 amps is maintained for 45 mins. During this time it deposits 4.572 gms of zinc at the cathode of a voltameter. E.C.E. of zinc is
The magnetic field at the centre of a circular current carrying-conductor of radius $r$ is $B_c$. The magnetic field on its axis at a distance $r$ from the centre is $B_a$. The value of $B_c$ : $B_a$ will be
→The magnetic susceptibility is
In a Rutherford scattering experiment when a projectile of charge $z_1$ and mass $M_1$ approaches a target nucleus of charge $z_2$ and mass $M_2$, the distance of closest approach is $r_0$ The energy of the projectile is
→