In the given circuit, the charge on $4\, \mu F$ capacitor will be.....$\mu C$
JEE MAIN 2019, Diffcult
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So total charge flow $=q=5.4\,\mu F \times 10\, V$
$=54\, \mu \mathrm{F}$
The charge will be distributed in the ratio of capacitance $\Rightarrow \quad \frac{q_{1}}{q_{2}}=\frac{2.4}{3}=\frac{4}{5}$
$\therefore \quad 9 X=54\, \mu C$
$\therefore \quad X=6\, \mu C$
Charge on $4 \,\mu F$ capacitor will be $=4 \mathrm{X}=4 \times 6\, \mu \mathrm{C}$
$=24\, \mu C$
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