In the given circuit the current I

Q: In the given circuit the current $I_1$ is .............. $A$

b (b) The circuit can be simplified as follows Applying $KCL$ at junction $A$ ${i_3} = {i_1} + {i_2}$.….$(i)$ Applying Kirchoff’s voltage law for the loop $ABCDA$ $ - 30{i_1} - 40{i_3} + 40 = 0$ $ \Rightarrow \,\,\,\,\,\, - 30{i_1} - 40({i_1} + {i_2}) + 40 = 0$ $ \Rightarrow \,\,\,\,\,\,\,7{i_1} + 4{i_2} = 4$ .….$(ii)$ Applying Kirchoff’s voltage law for the loop $ADEFA.$ $ - 40{i_2} - 40{i_3} + 80 + 40 = 0$ $ \Rightarrow \,\,\,\,\, - 40{i_2} - 40({i_1} + {i_2}) = - 120$ $ \Rightarrow \,\,\,\,\,\,{i_1} + 2{i_2} = 3\,$…….$(iii)$ On solving equation $(ii)$ and $(iii)$ ${i_1} = - 0.4\,A$.

SECTION - A [PHYSICS MCQ]

GSEB - English Medium

In the given circuit the current $I_1$ is .............. $A$

A$0.4$
B$-0.4$
C$0.8$
D$-0.8$

Diffcult

STD 11 Science
JEE
STD 12 - 3. current electricity
Physics

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