A thick wire is stretched so that its length become two times. Assuming that there is no change in its density, then what is the

Q: A thick wire is stretched so that its length become two times. Assuming that there is no change in its density, then what is the ratio of change in resistance of wire to the initial resistance of wire

c (c) In stretching $R \propto {l^2}$ $ \Rightarrow $ $\frac{{{R_2}}}{{{R_1}}} = \frac{{{l_2}^2}}{{{l_1}^2}}$ $ \Rightarrow $ $\frac{{{R_2}}}{{{R_1}}} = {\left( {\frac{2}{1}} \right)^2}$ $ \Rightarrow $${R_2} = 4{R_1}$. Change in resistance $ = {R_2} - {R_1} = 3{R_1}$ Now, $\frac{{{\rm{Change}}\,\,{\rm{in}}\,\,{\rm{resistance}}}}{{{\rm{Original}}\,\,{\rm{resistance}}}} = \frac{{3{R_1}}}{{{R_1}}} = \frac{3}{1}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A thick wire is stretched so that its length become two times. Assuming that there is no change in its density, then what is the ratio of change in resistance of wire to the initial resistance of wire

A$2:1$
B$4:1$
C$3:1$
D$1:4$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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