1 : 1 Solution: In $\triangle\text{ABC},$ $\text{AB = AC}\Rightarrow\angle\text{ABC}=\angle\text{ACB}...(\text{i})$ In $\triangle\text{OBC},$ $\text{OB = OC} \Rightarrow\angle\text{OBC}=\angle\text{OCB}...(\text{ii})$ Subtraction (ii) from (i), we get $\Rightarrow\angle\text{ABO}=\angle\text{ACO}$ So, $\angle\text{ABO}:\angle\text{ACO}=1:1$
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