Answer

  1. 1 : 1
    Solution:
    In $\triangle\text{ABC},$
    $\text{AB = AC}\Rightarrow\angle\text{ABC}=\angle\text{ACB}...(\text{i})$
    In $\triangle\text{OBC},$
    $\text{OB = OC} \Rightarrow\angle\text{OBC}=\angle\text{OCB}...(\text{ii})$
    Subtraction (ii) from (i), we get
    $\Rightarrow\angle\text{ABO}=\angle\text{ACO}$
    So, $\angle\text{ABO}:\angle\text{ACO}=1:1$

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