In the given figure, if the dimensions of the two wires are same but materials are different, then Young's modulus is $........$
Medium
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At same value of load
$A$ has less elongation than $B.......(1)$
$\frac{F L}{A Y}=\Delta L$ $\left\{\begin{array}{l}\because L, A \text { are same } \\ F \text { - Load is also taken same }\end{array}\right\}$
So $\frac{1}{Y} \propto \Delta L ......(2)$
Using conditions $(1)$ and $(2)$
We can say
$Y_A > Y_B \{$ Young's modulus of $A$ greater than $B\}$
$A$ has less elongation than $B.......(1)$
$\frac{F L}{A Y}=\Delta L$ $\left\{\begin{array}{l}\because L, A \text { are same } \\ F \text { - Load is also taken same }\end{array}\right\}$
So $\frac{1}{Y} \propto \Delta L ......(2)$
Using conditions $(1)$ and $(2)$
We can say
$Y_A > Y_B \{$ Young's modulus of $A$ greater than $B\}$
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