In the given figure, RS is a diameter of the circle. NM is parallel to RS and ∠MRS = 29°. Calculate: ∠RNM,
Exercise 17 (A) | Q 25.1 | Page 259
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Join RN and MS. ∴ ∠RMS = 90° (Angle in a semicircle is a right angle) ∴ ∠RSM = 90° - 29° = 61° (By angle sum property of triangle RMS) ∴ ∠RNM =180° ∠RSM =180° - 61° = 119° (pair of opposite angles in a cyclic quadrilateral are supplementary)
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