Question
In the given figure, $\triangle ABC$ is an equilateral triangle. Coordinates of vertices $A$ and $B$ are $(0, 3)$ and $(0, −3)$ respectively. Find the coordinates of points $C.$
✓
Answer
$AB = 6 \ cm = AC$
$ OC =\sqrt{36-9}=3 \sqrt{3} \ cm$
$\text { Point } C \text { is }(3 \sqrt{3}, 0)$
$ OC =\sqrt{36-9}=3 \sqrt{3} \ cm$
$\text { Point } C \text { is }(3 \sqrt{3}, 0)$
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