$P_A V_x^t=P_x V_x^t$

$10^2 \times(0.8)^{\frac{2}{2}}=3 \times 10^2\left(V_n\right)^{\frac{2}{1}}$

$\Rightarrow V_x=0.8 \times\left(\frac{1}{3}\right)^{0.2}=0.4$

Wodk doue in process $A \rightarrow B$

$W_{c x}=\frac{P_s V_0-P_x V_x}{\gamma-1}$

$\Rightarrow W_{\text {sx }}=\frac{10^2 \times 0.8-3 \times 10^2 \times 0.4}{\frac{5}{3}-1}$

$\Rightarrow W_{\text {As }}=-60 lJ =\Rightarrow\left|W_{\lambda \Omega}\right|=60 lJ$

Work done in process $B \rightarrow C$ (Isothermal process)

$W_{x=}=n R T / n \frac{V_8}{V_x}=P_x V_x \ell m \frac{V_8}{V_x}$

$\Rightarrow W_{x c}=3 \times 10^2 \times 0.4 \ln \frac{0.8}{0.4}$

$\Rightarrow W_{s c}=34 kJ$

Wodk doue in process $C \rightarrow A$

$W_{C_A}=P \Delta V=0 \quad(\because \Delta V=0)$

So toral work done in the process $A \rightarrow B \rightarrow C$

$W_{A B C}=W_{A \triangle}+W_{y C}+W_{C A}=-60+84+0$

$W_{A B C}=24 kJ$

So comect options are $(B,C.D)$