Question
In $\triangle\text{ABC}$ and $\triangle\text{DEF}$ its is given that $\angle\text{B}=\angle\text{E}$ and $\angle\text{C}=\angle\text{F}$ in order that $\triangle\text{ABC}≅\triangle\text{DEF}$ we must have,
✓
Answer
- BC = EF
Solution:
In $\triangle\text{ABC}$ and $\triangle\text{DEF}$
$\angle\text{B}=\angle\text{E}$ and $\angle\text{C}=\angle\text{F}$
For congruence, BC = EF
Therefore by AAS axiom
$\triangle\text{ABC}≅\triangle\text{DEF}$
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