In Young’s double-slit experiment, an interference pattern is obt… - Vidyadip

Question

In Young’s double-slit experiment, an interference pattern is obtained on a screen by a light of wavelength $6000 Å$, coming from the coherent sources $S_1$ and $S_2$. At certain point $ P $ on the screen third dark fringe is formed. Then the path difference $S_1P$ -$S_2P$ in microns is

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Answer

(b)For dark fringe at $P$
${S_1}P - {S_2}P = \Delta = (2n - 1)\lambda /2$
Here $n =3$ and $\lambda$ $ = 6000$
So, $\Delta = \frac{{5\lambda }}{2} = 5 \times \frac{{6000}}{2} = 15000Å = 1.5\;micron$

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