MCQ
In Young's double slit experiment how many maximas can be obtained on a screen (including the central maximum) on both sides of the central fringe if $\lambda = 2000\,{Å}$ and $d = 7000\,{Å}$
- A$12$
- ✓$7$
- C$18$
- D$4$
✓
Answer
Correct option: B.
$7$
b
(b) For maximum intensity on the screen
$d\sin \theta = n\lambda \Rightarrow \sin \theta = \frac{{n\lambda }}{d} = \frac{{n(2000)}}{{7000}} = \frac{n}{{3.5}}$
Since maximum value of $\sin \theta $ is $1$
So $n = 0,\,\,1,\,\,2,\,\,3,$ only. Thus only seven maximas can be obtained on both sides of the screen.
(b) For maximum intensity on the screen
$d\sin \theta = n\lambda \Rightarrow \sin \theta = \frac{{n\lambda }}{d} = \frac{{n(2000)}}{{7000}} = \frac{n}{{3.5}}$
Since maximum value of $\sin \theta $ is $1$
So $n = 0,\,\,1,\,\,2,\,\,3,$ only. Thus only seven maximas can be obtained on both sides of the screen.
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