Question
Instantaneous displacement current 1A in the space between the parallel plates of $1\mu\text{F}$ capacitor can be established by changing the potential difference at the rate of:
✓
Answer
- $\frac{10^6\text{V}}{\text{s}}$
In a capacitor of capacitance C,
$\text{V}=\frac{\text{q}}{\text{C}}$
$\Rightarrow\frac{\text{dV}}{\text{dt}}=\frac{\text{i}}{\text{C}}=\frac{1\text{A}}{1\mu\text{F}}=\frac{10^6\text{V}}{\text{s}}$
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