Question 11 Mark
If the frequency of EM radiations is halved then the energy of EM radiation will become:
View full question & answer→Question 21 Mark
Ultraviolet rays coming from sun are absorbed by:
View full question & answer→Question 31 Mark
The angular frequency of emf wave will be $($in $\frac{\text{rad}}{\text{s}})$
AnswerFrequency of wave $f = 40 \times 106 Hz$
Angular frequency, $\omega=2\pi\text{v}$
$\omega=2\pi\times40\times10^6$
$\Rightarrow\omega=8\pi\times10^7\frac{\text{rad}}{\text{s}}$
View full question & answer→Question 41 Mark
Which one of the following has the shortest wavelength?
View full question & answer→Question 51 Mark
An electric field $\overrightarrow{\text{E}}$ and a magnetic field $\overrightarrow{\text{B}}$ exist in a region. The fields are not perpendicular to each other.
Answer
- An electromagnetic wave may be passing through the region.
Explanation:
For an electromagnetic wave,electric field, magnetic field and direction of propagation are mutually perpendicular to each other. We can have a region in which electric and magnetic fields are applied at an angle with each other. In transmission lines Different modes exist. In transverse electric (TE) mode-no electric field exist in the direction of propagation. These are sometimes called H modes because there is only a magnetic field along the direction of propagation (His the conventional symbol for magnetic field).
View full question & answer→Question 61 Mark
Which of the following cannot travel in vacuum?
Answer
- Infrasonic waves
Explanation:
Radio waves, gamma waves, and infrared waves are electromagnetic waves and due to this they do not need any material medium to travel and hence, can travel in vacuum. Whereas, infrasonic waves are mechanical waves and so, they need a material medium to travel. Therefore, infrasonic waves cannot travel in vacuum.
View full question & answer→Question 71 Mark
The cellular mobile radio frequency band is:
View full question & answer→Question 81 Mark
If the magnetic field of an electromagnetic wave is given as $B_{y }= 2 \times 10^{-7} \sin(10^3x + 1.5 \times 10^{12}t)$ tesla, the wavelength of the electromagnetic wave is.
AnswerThe general equation of an electromagnetic wave is $\text{B = A}\sin(\text{kx + }\omega\text{t})$
Comparing this equation with the given equation, $A = 2 \times 10^{-7}, k = 10^3$ and $\omega = 1.5 \times 10^{12}$
So, $10^3=\frac{2\pi}{\lambda}$
or $\lambda=6.28\times10^{-3}\text{m}$
$=6.28\ \text{mm}$
View full question & answer→Question 91 Mark
A plane electromagnetic wave with a single frequency moves in vacuum in the positive x direction. Its amplitude is uniform over the yz plane. the amplitude of its magnetic field.
Answer
- same
Explanation:
The same amount of energy passes through equal areas parallel to the yz plane as the wave travels in the +x direction, so the amplitude and the intensity, which is proportional to the square of the amplitude, do not change.
View full question & answer→Question 101 Mark
Which of the following is not true for electromagnetic waves?
Answer
- They travel at different speeds in air depending on their frequency.
Explanation:
They travel at different speed in air depending on their frequency. At constant as the speed will be same irrespective of frequency. Also frequency is source dependent and doesn't controls speed.
View full question & answer→Question 111 Mark
A plane electromagnetic wave of frequency $28 \ MHz$ travels in free space along the positive $x-$direction. At a particular point in space and time, electric field is $9.3\ V/m$ along positive $y-$direction. The magnetic field $($in $T)$ at that point is
Answer$\text{B}=\frac{\text{E}}{\text{C}}$
$=\frac{9.3}{3\times10^8}$
$=3.1\times10^{-8}$
View full question & answer→Question 121 Mark
When is the conduction current the same as the displacement current?
Answer
- When the source is ac
Explanation:
The conduction current is the same as the displacement current when the source is ac.
View full question & answer→Question 131 Mark
An EM wave of intensity I falls on a surface kept in vacuum and exerts radiation pressure p on it. Which of the following are true?
Answer
- Radiation pressure is I/c if the wave is totally absorbed.
- Radiation pressure is 2I/c if the wave is totally reflected.
- Radiation pressure is in the range I/c < p < 2I/c for real surfaces.
Solution:
Key concept: Radiation pressure (p) is the force exerted by electromagnetic wave on unit area of the surface, i.e., rate of change of momentum per unit area of the surface.
Let us consider a surface exposed to electromagnetic radiation as shown in figure. The radiation is falling normally on the surface. Further, intensity of radiation is I and area of surface exposed to radiation is A.

E = Energy received by surface per second = I.A
N = Number of photons received by surface per second
$\text{N}=\frac{\text{E}}{\text{E}_\text{Photon}}=\frac{\text{E}\lambda}{\text{hc}}=\frac{\text{IA}\lambda}{\text{hc}}$
Now, there are three cases possible which are as follows.
CaseI:
Surface is perfectly reflecting
$\Delta\text{P}_\text{one photon}=\text{Change in momentum}=\frac{2\text{h}}{\lambda}$
$\therefore\ \text{Total force experienced F}=\text{N}\times\Delta\text{P}_\text{one photon}=\frac{2\text{IA}}{\text{c}}$
Also, pressure $\text{P}=\frac{\text{F}}{\text{A}}=\frac{2\text{I}}{\lambda}$
Case II:
Surface is perfectly absorbing
$\Delta\text{P}_\text{one photon}=\frac{\text{h}}{\lambda}$
$\Rightarrow\ \text{F}=\text{N}\times\Delta\text{P}_\text{one photon}=\frac{\text{IA}}{\text{c}}$
Also, Pressure $\text{P}=\frac{\text{F}}{\text{A}}=\frac{\text{I}}{\text{c}}$
Hence radiation pressure is in the range $\frac{\text{I}}{\text{C}}<\text{P}<\frac{2\text{I}}{\text{c}}$ for real surfaces.
Important Points:
If surface is partly reflecting
Let us consider that surface reflects 70% and absorbs 30% of the incident radiation.
$\text{F}=0.7\Big(\frac{2\text{IA}}{\text{c}}\Big)+0.3\Big(\frac{\text{IA}}{\text{c}}\Big)=\frac{1.7\text{IA}}{\text{c}}$
Remarks:
- Radiation force/pressure supports photon theory of radiation.
- If radiation falls abliquely, then appropriate projection of area vector is taken.

For situation as shown in figure,
$\text{F}=\frac{2\text{IA}\cos^2\theta}{\text{c}}$, for perfectly reflecting surface
$\text{F}=\frac{\text{IA}\cos\theta}{\text{c}}$, for perfectly absorbing surface
$\text{F}=\frac{1.4\text{IA}\cos^2\theta}{\text{c}}+\frac{0.3\text{IA}\cos \theta}{\text{c}}$, for partially reflecting surface. View full question & answer→Question 141 Mark
An electromagnetic wave, going through vacuum is described by $\text{E}=\text{E}_0\sin(\text{kx}-\omega\text{t}.)$ Which of the following is independent of wavelength?
Answer
- $\frac{\text{k}}{\omega}$
Explanation:
$\text{k}=\frac{2\pi}{\lambda}$
$\omega=\frac{2\pi\text{c}}{\lambda},$ where c is the velocity of light
Hence, $=\frac{\text{k}}{2\pi}=\frac{\omega}{2\pi\text{c}}$
$\Rightarrow\frac{\text{k}}{\omega}$ is independent of the wavelength.
View full question & answer→Question 151 Mark
When electromagnetic waves enter the ionised layer of ionosphere, then the relative permittivity i.e. dielectric constant of the ionised layer:
View full question & answer→Question 161 Mark
According to Maxwell's equation, the velocity of light in any medium is expressed as.
Answer
- $\frac{1}{\sqrt\mu\epsilon}$
Explanation:
Velocity of light in a medium,
$\text{c}=\frac{1}{\sqrt{\mu_0\epsilon_0\mu_\text{r}\epsilon_\text{r}}}=\frac{1}{\mu_0\epsilon_0}$ View full question & answer→Question 171 Mark
Electromagnetic waves travel only through.
Answer
- oscillating electric and magnetic fields whose directions are perpendicular to each other
Explanation:
Electromagnetic waves travel through oscillating electric and magnetic fields whose directions are perpendicular to each other.
View full question & answer→Question 181 Mark
Displacement current goes through the gap between the plates of a capacitor when the charge of the capacitor:
Answer
- Increases.
- Decreases.
Explanation:
Displacement current inside a capacitor,
$\text{i}_\text{d}=\epsilon_0\frac{\text{d}\phi_\text{E}}{\text{dt}},$ where
$\phi_\text{E}$ is the electric flux inside the capacitor.
Up to the time the electric flux changes, there will be a displacement current. This is possible when the charge on a capacitor changes. Therefore, the displacement current goes through the gap between the plates of a capacitor when the charge of the capacitor or electric field increases or decreases inside the capacitor. View full question & answer→Question 191 Mark
Which of the following radiations are used to treat muscle ache?
Answer
- Infrared Rays
Explanation:
Infrared rays are used to treat muscle aches.
View full question & answer→Question 201 Mark
Choose the correct answer from the alternatives given.
The amplitude of an electromagnetic wave in vaccum is doubled with no other changes made to the wave. As a result of this doubling of the amplitude, which of the following statement is correct?
Answer
- None of the above is correct
Explanation:
As we know, velocity of electromagnetic wave,
$\text{c}=\frac{1}{\sqrt{\mu_0\epsilon_0}}=\frac{3\times10^8\text{m}}{\text{s}}$
which is constant
So It is independent of amplitude of electromagnetic wave, frequency and wavelength of electromagnetic wave.
so none of the above is correct. View full question & answer→Question 211 Mark
A plane electromagnetic wave travels in vacuum along $\hat{\text{k}}$ direction, where $\hat1\hat{\text{j}}$ and $\hat{\text{k}}$ are unit vectors along the x, y and z directions. The direction along which the electric and the magnetic field vectors point may be respectively.
Answer
- $\hat{\text{k}}\text{ and }\hat{\text{j}}$
Explanation:
Electromagnetic wave is a transverse wave that means the electric and magnetic field associated to it will not only be perpendicular to each other but will also be
perpendicular to the direction in which the wave travels.
So, if waves travel along $\hat{\text{k}}$ direction then the electric and the magnetic field will be along $\hat{\text{i}}$ and $\hat{\text{j}}$ directions. View full question & answer→Question 221 Mark
Choose the correct answer from the alternatives given.
The conduction current is the same as displacement current when the source is.
Answer
- AC only
Explanation:
For a capacitor, we have:
Q = CV
If Q is changing, there will be a current in capacitor plates,
$\text{I}=\frac{\text{dQ}}{\text{dt}}=\frac{\text{CdV}}{\text{dt}}$when voltage across the capacitor is constant, $\frac{\text{dV}}{\text{dt}}=0$
therefore, I = 0
It implies that, for a DC (constant) voltage, the capacitor current is zero.
Hence, for a DC source the conduction current and displacement current (capacitor current) are not same.
Whereas, by Maxwell's equation for a time varying voltage (AC voltage), both conduction and displacement currents are same. View full question & answer→Question 231 Mark
10cm is a wavelength corresponding to the spectrum of:
Answer
- Microwaves
Explanation:
Microwaves have wavelength around 10cm.
View full question & answer→Question 241 Mark
The condition under which a microwave over heats up a food item containing water molecules most efficiently is:
Answer
- The frequency of the microwaves must match the resonant frequency of the water molecules.
Explanation:
When frequency of microwave matches with frequency of water molecules i.e., resonant condition. Maximum energy is transferred to water molecules as their K.E. energy.
View full question & answer→Question 251 Mark
Which of the following type of radiations are radiated by on oscillating electric charge?
Answer
- Electromagnetic
Explanation:
Any stationary charge produce static electric field. And the field strength is given by:
r, is the radial distance from the point charge.
Q, is the charge in Coulomb.
When electric charge oscillates electric field at any point also oscillates.And according to Maxwell's equations varying electric field produces magnetic field and an oscillating electric field produces oscillating magnetic field. This thing is used in antennas in which oscillating current of certain frequency produces oscillating electric and magnetic field which propagates through space(electromagnetic waves).
View full question & answer→Question 261 Mark
Two opposite charged particles oscillate about their mean equilibrium position in free space, with a frequency of $10^9 \ Hz.$ The wavelength of the corresponding electromagnetic wave produced is $.........:$
AnswerElectromagnetic wave $V = 3\times 10^8m/s$
Given frequency $(f) = 10^9Hz$
$\text{V}=\text{f}\lambda$
$\lambda=\frac{\text{V}}{\text{f}}$
$=\frac{3 \times 10^8} {10^9}$
$= 0.3m$
View full question & answer→Question 271 Mark
Which of the following effects could not be explained by Maxwell's electromagnetic wave theory?
Answer
- All of these
Explanation:
- Photoelectric effect was discovered by heinrich Rudoy Hertz.
- Compton effect was discovered by Aethur Holl Compton.
- Raman effect was discovered by Sir Chandrasekhar Venbata Ram.
So, none of these effect was discovered by Maxwell.
View full question & answer→Question 281 Mark
A charged particle oscillates about its mean equilibrium position with a frequency of $109 \ Hz.$ The frequency of electromagnetic waves produced by the oscillator is$:$
View full question & answer→Question 291 Mark
The ozone layer in the atmosphere absorbs:
Answer
- X-rays and ultraviolet rays
View full question & answer→Question 301 Mark
An electromagnetic wave can be produced when the charge is
Answer
- Both (a) and (c)
Explanation:
An accelerated charge is the source of electromagnetic waves (EMWs). When the charge is in a circular motion, the direction of its velocity continuously changes and thus it is in accelerated motion and produces EMWs. A charge falling in an electric field is accelerated by the electric force and thus produces EMWs.
View full question & answer→Question 311 Mark
A $1000\Omega$ resistance and a capacitor of $100\Omega$ resistance are connected in series a 220V source. when the capacitor is 50% charged, the value of the displacement current is.
Answer
- 2.2A
Explanation:
Displacement current $=\text{I}_\text{D}=\text{C}\frac{\text{dV}}{\text{dT}}=\text{C}\omega\text{V}_\text{o}=\frac{\text{V}_\text{o}}{\text{X}_\text{c}}=\frac{220\text{V}}{100\Omega}=2.2\text{A}$
As we are asked amplitude of displacement current. So, we don't have to worry about charge on capacitor. View full question & answer→Question 321 Mark
A plane electromagnetic wave of frequency $20 \ MHz$ travels through a space along $x$ direction. If the electric field vector at a certain point in space is $6 \ Vm^{-1},$ what is the magnetic field vector at that point?
AnswerVelocity of $EM$ wave $\text{v}=\frac{3\times10^8\text{m}}{\text{s}}$
Electric field vector $\text{E}=\frac{6\text{V}}{\text{m}}$
Thus magnetic field vector $\text{B}=\frac{\text{E}}{\text{v}}$
$\therefore\text{B}=\frac{6}{3\times10^8}$
$=2\times10^{-8}\text{T}$
View full question & answer→Question 331 Mark
Which waves are used by artificial satellites for communication?
Answer
- Microwaves
Explanation:
Microwaves are used by artificial satellites for communication.
View full question & answer→Question 341 Mark
The energy contained in a small volume through which an electromagnetic wave is passing oscillates with:
Answer
- Double the frequency of the wave.
Explanation:
The energy per unit volume of an electromagnetic wave,
$\text{u}=\frac{1}{2}\in_0\text{E}^2+\frac{\text{B}^2}{2\mu_0}$
The energy of the given volume can be calculated by multiplying the volume with the above expression.
$\text{U}=\text{u}\times\text{V}=\Big(\frac{1}{2}\in_0\text{E}^2+\frac{\text{B}^2}{2\mu_0}\Big)\times\text{V}\ ....(\text{i})$
Let the direction of propagation of the electromagnetic wave be along the z-axls. Then, the electric and magnetic fields at a particular point are given by,
$\text{E}_\text{x}=\text{E}_0\sin(\text{kz}-\omega\text{t})$
$\text{B}_\text{y}=\text{B}_0\sin(\text{kz}-\omega\text{t})$
Substituting the values of electric and magnetic fields in (1) we get,
$\text{U}=\Big(\frac{1}{2}\in_0\big(\text{E}_0^2\sin^2(\text{kz}-\omega\text{t})+\frac{\text{B}^2_0\sin^2(\text{kz}-\omega\text{t})}{2\mu_0}\Big)\times\text{V}$
$\text{U}=\Big(\in_0\text{E}^2_0\frac{(1-\cos(2\text{kz}-2\omega\text{t}))}{4}+\frac{\text{B}_0^2(1-\cos(2\text{kz}-2\omega\text{t}))}{4\mu_0}\Big)\times\text{V}$
From the above expression, it can be easily understood that the energy of the electric and magnetic fields have angular frequency $2\omega$ Thus. the frequency of the energy of the electromagnetic wave will also be double. View full question & answer→Question 351 Mark
From Maxwell’s hypothesis, a charging electric field gives rise to:
Answer
- a magnetic field.
Explanation:
A charging electric field gives rise to a magnetic field.
View full question & answer→Question 361 Mark
Light with an energy flux of $20W/cm^2$ falls on a non$-$reflecting surface at normal incidence. If the surface has an area of $30\ cm^2$. the total momentum delivered $($for complete absorption$)$ during $30$ minutes is:
AnswerGivne energy flux $\phi=20\frac{\text{W}}{\text{cm}^2}$
Area, $A = 30\ cm^2$
Time, $t = 30min = 30 \times 60s$
Now, total energy falling on the surface in time $t$ is,
$\text{U}=\phi\text{At}=20\times30\times(30\times60)\text{J}$
Momentum of the incident light $=\frac{\text{U}}{\text{c}}$
$=\frac{20\times30\times(30\times60)}{3\times10^{8}}=36\times10^{-4}\text{kg-ms}^{-1}$
Momentum of the reflected light $= 0$
$\therefore$ Momentum delivered to the surface
$=36\times10^{-4}-0=36\times10^{-4}\text{kg-ms}^{-1}$
Important points
Mass of photon:
Actually rest mass of the photon is zero. But its effective mass is given as $\text{E}=\text{mc}^2=\text{hv}$
$\Rightarrow\ \text{m}=\frac{\text{E}}{\text{C}^2}=\frac{\text{hv}}{\text{C}^2}=\frac{\text{h}}{\text{c}\lambda}$. Thsi mass is also known as kintic mass of the photon.
Momentum of the photon:
Momentum $\text{p}=\text{m}\times\text{c}=\frac{\text{E}}{\text{c}}=\frac{\text{hv}}{\text{c}}=\frac{\text{h}}{\lambda}$
Number of emitted photons:
The number of photons emitted per second from a source of monochromatic radiation of wavelengh $\lambda$ and power $P$ is given as $\text{(n)}=\frac{\text{P}}{\text{E}}=\frac{\text{P}}{\text{hv}}=\frac{\text{P}\lambda}{\text{hc}}$; where $E =$ energy of each photon
Inrensity of light $(I):$
Energy crossing per unit area normally per second is called intensity or energy flux
i.e. $\text{I}=\frac{\text{E}}{\text{At}}=\frac{\text{P}}{\text{A}}\Big(\frac{\text{E}}{\text{t}}=\text{P}=\text{radiation Power}\Big)$
At a distance r from a point source of power $P$ intensity is given by $\text{I}=\frac{\text{P}}{4\pi\text{r}^2}\Rightarrow\ \text{I}\propto\frac{1}{\text{r}^2}$.
View full question & answer→Question 371 Mark
The frequency of incident light falling on a photosensitive metal plate is doubled, the kinetic energy of the emitted photoelectrons is.
Answer$v \rightarrow 2v hv − hv_o = KG_{max}$
So, $KG_{max} > 2KG_{max}$
as $hv_o$ is constant
View full question & answer→Question 381 Mark
What is the frequency of electromagnetic waves in a vacuum that have the same wavelength as a $500.0 \ Hz$ sound wave moving at $\frac{345\text{m}}{\text{s}}$?
Answer$4.35 \times 10^8 \ Hz$
View full question & answer→Question 391 Mark
The waves which are electromagnetic in nature are:
Answer
- Light waves and X-rays
Explanation:
Light waves and X-rays are electromagnetic waves.
View full question & answer→Question 401 Mark
Dimensions of $\frac{1}{(\mu_0\epsilon_0)}$ is:
Answer
- $\frac{\text{L}^2}{\text{T}^2}$
Explanation:
The speed of light, $\text{C}=\frac{1}{\sqrt{\mu_0\epsilon_0}}$
The dimensions of $\frac{1}{\sqrt{\mu_0\epsilon_0}}$ are of velocity, i.e., $\frac{\text{L}}{\text{T}}$
Therefore, $\frac{1}{\epsilon_0\mu_0}$ will have dimensions $\frac{\text{L}^2}{\text{T}^2}$ View full question & answer→Question 411 Mark
A. Current flow inside the capacitor due to accumulation of charges on the capacitor walls is called displacement current.
B. Current due to the flow of electrons due to some potential difference is called as conduction current.
C. Displacement current came into existence when Maxwell observed that if a magnetic compass is placed between the capacitors the needle gets deflected which signifies presence of magnetic fields which would possibly caused due to some changing current.
D. Displacement current change the actual motion of electric charges.
Which of the above statement(s) is/ are correct?
Answer
- A, B and C only
Explanation:
Displacement current is a quantity appearing in Maxwell's equations that is defined in terms of the rate of change of electric displacement field. Displacement current came into existence when Maxwell observed that if a magnetic compass is placed between the capacitors the needle gets deflected which signifies presence of magnetic fields which would possibly caused due to some changing current. Current flow inside the capacitor due to accumulation of charges on the capacitor walls is called displacement current.However it is not an electric current of moving charges, but a 'time-varying electric field'.
View full question & answer→Question 421 Mark
Electromagnetic wave of intensity $1400 \ W/m^2$ falls on metal surface on area $1.5m^2$ is completely absorbed by it. Find out force exerted by beam.
AnswerFor a perfectly absorbing surface,
$\text{F}=\frac{\text{IA}}{\text{C}}$
$=\frac{(1400\text{W/m}^2×1.5\text{m}^2)}{(3×10^8\text{m/s})}$
$=7\times10^{−6}\text{N}.$
View full question & answer→Question 431 Mark
The ratio of contributions made by the electric field and magnetic field components to the intensity of an $\ce{EM}$ wave is:
AnswerThe intensity of electromagnetic wave is given by,
$I = U_{av}c,$ where $U_{av} =$ Average energy and $c =$ speed of light
Intensity in relation with electric field $\text{U}_\text{av}=\frac{1}{2}\epsilon_0\text{E}_0^2$
Intensity relation with magnetic field $\text{U}_\text{av}=\frac{1}{2}\frac{\text{B}_0^2}{\mu_0}$
Now taking the intensity in terms of electric field,
$(\text{U}_\text{av})_\text{electric field}=\frac{1}{2}\epsilon_0\text{E}_0^2=\frac{1}{2}\epsilon_0(\text{cB}_0)^2\ \ (\because\ \text{E}_0=\text{cB}_0)$
But, $\text{c}=\frac{1}{\sqrt{\mu_0\epsilon_0}}$
$\therefore\ (\text{U}_\text{av})_\text{Electric field}=\frac{1}{2}\epsilon_0\times\frac{1}{\mu_0\epsilon_0}\text{B}_0^2=\frac{1}{2}\frac{\text{B}_0^2}{\mu_0}$
$=(\text{U}_\text{av})_\text{magnetic field}$
Hence the energy in electromagnetic wave is divided equally between electric field vector and magnetic field vector.
It means the ratio of contributions by the electric field and magnetic field components to the intensity of an electromagnetic wave is $1:1.$
Impotant point:
Propertioe of $\ce{EM}$ waves
Speed: In free, its speed $\text{c}=\frac{1}{\sqrt{\mu_0\epsilon_0}}$
$=\frac{\text{E}_0}{\text{B}_0}$
$=3\times10^8\text{m/s}.$
In medium $\text{v}=\frac{1}{\sqrt{\mu\epsilon}};$
where $\mu_0 =$ Absolute permeability, $\epsilon_0 =$ Absolute permittivity, $E_0$ and $B_0 =$ Amplitude of electric of field and magnetic field vectors.
Energy: The energy in an $\ce{EM}$ waves is divided equally between the electric and magnetic fields.
Energy density of electric field $\text{u}_\text{e}=\frac{1}{2}\epsilon_0\text{E}^2,$
Energy density of magnetic field $\text{u}_\text{B}=\frac{1}{2}\frac{\text{B}^2}{\mu_0}$
It is found that $u_e = u_B.$
Also $\text{u}_\text{av}=\text{u}_\text{e}+\text{u}_\text{B}=2\text{u}_\text{e}=2\text{u}_\text{B}=\epsilon_0\text{E}^2=\frac{\text{B}^2}{\mu_0}$
Intensity $(I):$ The energy crossing per unit area unit time, perpendicular to the direction of propagation of $\ce{EM}$ wave is called intensity.
$\text{I}=\text{u}_\text{av}\times\text{c}=\frac{1}{2}\epsilon_0\text{E}^2\text{c}=\frac{1}{2}\frac{\text{B}^2}{\mu_0}.\text{c}$
Momentum: $\ce{EM}$ waves also carries momentum, if a portion of $\ce{EM}$ wave of energy $u$ propagating with speed $c,$ then linear momentum $=\frac{\text{Energy (u)}}{\text{Speed (c)}}$
When the incident $\ce{EM}$ wave is completely absorbed by a surface, it delivers energy u and momentum $u/c$ to the surface.
When a wave of energy us is totally reflected from the surface, the momentum delivered to surface is $2u/c.$
Poynting vector $(\vec{\text{S}})$: In $\ce{EM}$ waves, the rate of flow of energy crossing a unit area is described by the poynting vector. Its unit is $\ce{watt/m^2}$ and $\vec{\text{S}}=\frac{1}{\mu_0}(\vec{\text{E}}\times\vec{\text{B}})=\text{c}^2\epsilon_0(\vec{\text{E}}\times\vec{\text{B}})$.
Because in $\ce{EM}$ waves, $\vec{\text{E}}$ and $\vec{\text{B}}$ are perpendicular to each other, the magnitude of $\vec{\text{S}}$ is $|\vec{\text{S}}|=\frac{1}{\mu_0}\text{E B}\sin90^\circ=\frac{\text{EB}}{\mu_0}=\frac{\text{E}^2}{\mu_\text{C}}$.
The direction of the Poynting vector $\vec{\text{S}}$ at any point gives the wave's direction of travel and direction of energy transport the point.
Radiation Pressure: Is the momentum imparted per second per unit area on which the light falls.
For a perfectly reflecting surface $\text{P}_\text{r}=\frac{2\text{S}}{\text{c}}$;
$S =$ Poynting vector; $c =$ speed of light
For a perfectly absorbing surface $\text{P}_\text{a}=\frac{\text{S}}{\text{c}}$.
The radiation pressure is real that's why tails of comet point away from the sun.
View full question & answer→Question 441 Mark
An AM radio wave is emitted by a radio antenna and travels across flat ground. Find out the direction of the magnetic field component of the wave?
Answer
- Parallel to the ground and perpendicular to the direction of propagation
Explanation:
According to Maxwell an accelerated charge produces a sinusoidal time varying magnetic field which in turn produces a time varying electric field .The two fields so produced are mutually perpendicular to each other and constitute an electromagnetic wave and propagate in space in the direction perpendicular to both the fields. An AM wave is also an electromagnetic wave therefore its magnetic field component would be parallel to ground and perpendicular to the direction of propogation.
View full question & answer→Question 451 Mark
The matter-wave picture of electromagnetic wave/radiation elegantly incorporated the:
Answer
- Heinsenbergs uncertainty principle
Explanation:
The matter-wave picture of electromagnetic wave/radiation elegantly incorporated the Heisenberg uncertainty principle.
View full question & answer→Question 461 Mark
In the propagation of electromagnetic waves, the angle between the direction of propagation and plane of polarisation is
Answer
- 0°
Explanation:
Plane of polarization is a confinement of the electric/ magnetic field vector to a given plane along the direction of propagation. Therefore angle between them is 0°.
View full question & answer→Question 471 Mark
The polarisation of electromagnetic wave is in:
Answer
- The directions of electric field
View full question & answer→Question 481 Mark
Mark the correct option in impure spectrum:
Answer
- Colours are overlapped
Explanation:
The order of colours is are straight, hence option a is false.
Order of colours are regular.
Colours are overlapped each other in impure spectrum.
Colours are present in impure spectrum.
View full question & answer→Question 491 Mark
Which of the following proves that electromagnetic waves are transverse?
Answer
- Polarisation
Explanation:
Only transverse waves can be polarised.
View full question & answer→Question 501 Mark
Which among the following has a frequency range of 500 kHz to 1000 MHz?
Answer
- Radio Waves
Explanation:
Radio Waves are generally in the frequency range ➔ 500 kHz to 1000 MHz. Radio waves are used for long-distance communication, such as in television, mobiles, and radios. These devices receive radio waves and convert them to mechanical vibrations in the speaker to create sound waves.
View full question & answer→Question 511 Mark
What is the phase difference between electric and magnetic fields in an electromagnetic wave?
Answer
- $\pi$
Explanation:
The phase difference between electric and magnetic fields in an electromagnetic wave is$\pi$. View full question & answer→Question 521 Mark
Which of the following has/have zero average value in a plane electromagnetic wave?
Answer
- Both magnetic and electric field
View full question & answer→Question 531 Mark
A plane electromagnetic wave with a single frequency moves in vacuum in the positive x direction. Its amplitude is uniform over the yz plane its wavelength:
Answer
- Same
Explanation:
The same amount of energy passes through equal areas parallel to the yz plane as the wave travels in the +x direction, so the amplitude and the intensity, which is proportional to the square of the amplitude, do not change.
View full question & answer→Question 541 Mark
Choose the correct answer from the alternatives given.
Displacement current goes through the gap between the plates of a capacitor when the charge of the capacitor.
Answer
- increases or decreases
Explanation:
Displacement current inside a capacitor is given by:-
$\text{i}_\text{d}=\epsilon_0\frac{\phi\text{E}}{\text{dt}}$
where $\phi_\text{E}$ is the electric flux inside the capacitor
The displacement current is developed inside a capacitor when there is a change in the electric flux linked with the capacitor.
The change in electric flux can occur in both the cases either the charge increases or decreases on the capacitor. This will lead to a change in flux linked with the coil. View full question & answer→Question 551 Mark
In the propagation of light waves, the angle between the plane of vibration & plane of polarisation is:
Answer
- 90°
Explanation:
The plane of polarisations is that plane in which there is no vibration. While a plane including the direction of light propagation and the direction of electric field is called the plane of vibration. The angle between them is 90°.
View full question & answer→Question 561 Mark
Who first proposed the light as an electromagnetic wave?
Answer
- James Clerk Maxwell
Explanation:
In 1864, Maxwell predicted the existence of electromagnetic waves, the existence of which had not been confirmed before that time, and out of his prediction came the concept of light being a wave, or more specifically, a type of electromagnetic wave. It is a wide intuition that Albert Einstein proposed the dual nature theory but is not correct.
View full question & answer→Question 571 Mark
A magnetic field can be produced by:
Answer
- Both of them.
Explanation:
According to Ampere-Maxwell's Law, a magnetic field is produced due to the conduction current in a conductor and the displacement current. The conduction current is actually the motion of the charge. The displacement current is due to the changing electric field. The displacement current is given by,
$\text{i}_\text{d}=\epsilon_0\frac{\text{d}\phi_\text{E}}{\text{dt}}$ $\big(\because\phi_\text{E}$ is the electric flux$\big)$
Thus, the magnetic field is produced by the moving charge as well as the electric field. View full question & answer→Question 581 Mark
The wavelength of the wave is.
Answer
- 7.5m
Explanation
Using $\text{v}=\text{v}\lambda$ where v is the speed of EM wave.
As $\text{V}=\text{c}=3\times\frac{10\text{m}}{\text{s}}$
$\Rightarrow3\times10^8=40\times10^6\lambda$
$\Rightarrow\lambda=7.5\text{m}$ View full question & answer→Question 591 Mark
A linearly polarized electromagnetic wave given as $\text{E}=\text{E}_0\hat{\text{i}}\cos(\text{kz}-\omega\text{t})$ is incident normally on a perfectly reflecting infinite wall at z = a. Assuming that the material of the wall is optically inactive, the reflected wave will be given as:
Answer
- $\text{E}_\text{r}=\text{E}_0\hat{\text{i}}\cos(\text{kz}+\omega\text{t})$
Solution:
Key concept: When a wave is reflected from a denser medium or perfectly reflecting wall made with optically inactive material, then the type of wave doesn't change but only its phase changes by 180º or $\hat{\text{I}}€$ radian. View full question & answer→Question 601 Mark
In case of the electromagnetic waves the angle between the electric and magnetic field vectors is.
Answer
- $\frac{\pi}{2}$
Explanation:
Electromagnetic waves are formed when an electric field couples with a magnetic field. The magnetic and electric fields of an electromagnetic wave are perpendicular to each other and to the direction of the wave, as shown in figure. View full question & answer→Question 611 Mark
In an electromagnetic wave, the direction of the magnetic induction B is
Answer
- perpendicular to the electric field $\overrightarrow{\text{S}}$
Explanation:
The electric field is always perpendicular to the magnetic field, and both fields are directed at right-angles to the direction of propagation of the wave. In fact, the wave propagates in the direction $\overrightarrow{\text{E}}\times\overrightarrow{\text{B}}$ Electromagnetic waves are clearly a type of transverse wave. View full question & answer→Question 621 Mark
Electromagnetic waves are produced by:
Answer
- An accelerating charge.
Explanation:
A static charge produces an electrostatic field. A moving charge produces a magnetic field. Electromagnetic waves are produced by an accelerating charge.
View full question & answer→Question 631 Mark
According to Maxwell’s Hypothesis, a changing electric field gives rise to?
Answer
- Magnetic Field
Explanation:
A changing electric field gives rise to a magnetic field.
View full question & answer→Question 641 Mark
Pick out the correct increasing order of energy of electromagnetic waves from the following:
AnswerThe energy of electromagnetic waves is directly proportional to the frequency of the electromagnetic waves.
So the order of frequency is given as:
$v_{micro }< v_{infrared} < v_{visible }< v_{ultraviolet} < v_{gamma}$
Since $E = hv$
$➔ \text{E} \propto\text{v}$
The order of energy is as follows:
$E_{micro} < E_{infrared} < E_{visible} < E_{ultraviolet} < E_{gamma}$
View full question & answer→Question 651 Mark
An electromognetic wave travels in vacuum along z direction: $\text{E}=\big(\text{E}_1\hat{\text{i}}+\text{E}_2\hat{\text{j}}\big)\cos(\text{kz}-\omega\text{t})$. Choose the correct options from the following:
Answer
- The associated magnetic field is given as $\text{B}=\frac{1}{\text{c}}\big(\text{E}_1\hat{\text{i}}+\text{E}_2\hat{\text{j}}\big)\cos(\text{kz}-\omega\text{t})$.
- The given electromagnetic wave is plane polarised.
Solution:
We are given that the electric field vector of an electromagnetic wave travels in a vacuum along z-direction as,
$\vec{\text{E}}=\big(\text{E}_2\hat{\text{i}}+\text{E}_2\hat{\text{j}}\big)\cos(\text{kz}-\omega\text{t})$
The magnitude of the electric and the magnetic fields in an electronagnetic wave are related as
$\text{B}_0=\frac{\text{E}_0}{\text{c}}$
$\vec{\text{B}}=\frac{\vec{\text{E}}}{\text{c}}=\frac{\text{E}_1\text{i}+\text{E}_2\text{i}}{\text{c}}\cos(\text{kz}-\omega\text{t})$
Also, $\vec{\text{E}}$ and $\vec{\text{B}}$ are perpendicular to each other and the propagation of electromagnetic wave is perpendicular to $\vec{\text{E}}$ as well as $\vec{\text{B}}$, so the given electromagnetic wave is plane polarized. View full question & answer→Question 661 Mark
Unpolarized light falls first on polarizer (P) and then on analyzer (A). If the intensity of the transmitted light from the analyser is $\frac{1}{8}\text{th}$ of the incident unpolarized light. What will be the angle between optic axes of P and A?
Answer
- 60°
Explanation:
Given,
$\text{I}=\frac{\text{I}_\text{0}}{2}....(\text{i})$
$\text{I}=\text{I}\cos^2\theta$ $\Big(\because\text{I}=\frac{\text{I}_0}{8}\Big)$
$\therefore\frac{\text{I}_0}{8}=\frac{\text{I}_0}{2}\cos^2\theta$
From the equation (i), we have
$\frac{1}{4}=\cos^2\theta$
$\Rightarrow\cos\theta=\frac{1}{2}$
$\Rightarrow\cos\theta=\cos60^\circ$
$\Rightarrow\theta=60^\circ$ View full question & answer→Question 671 Mark
Radiations of intensity $\frac{0.5\text{W}}{\text{m}^2}$ are striking a metal plate. The pressure on the plate is.
Answer
- $\frac{0.166\times10^{-8}\text{N}}{\text{m}^2}$
Explanation:
Intensity or power per unit area of the radiations,
P = pv
$\Rightarrow\text{P}=\frac{\text{P}}{\text{v}}=\frac{0.5}{3\times10^8}=\frac{0.166\times10^{-8}\text{N}}{\text{m}^2}$ View full question & answer→Question 681 Mark
A parallel plate capacitor consists of two circular plates each of radius 12cm and separated by 5.0mm. The capacitor is being charged by an external source. The charging current is constant and is equal to 0.15A.The displacement current is:
Answer
- 0.15A
Explanation:
According to Maxwell's hypothesis, a displacement current will flow through a capacitor when the potential difference across its plates is varying.
Thus a varying electric field will exist between the plates and this displacement current is same in magnitude to the current flowing in outer circuit.
Here, the current in the outer circuit is 0.15 A. Thus 0.15A will be the displacement current.
View full question & answer→Question 691 Mark
Infrared radiation are detected by:
Answer
- Photometre
Explanation:
Infrared radiation is detected by photometer.
View full question & answer→Question 701 Mark
According to the electromagnetic wave theory, light consists of electric and magnetic fields which are_____________.
Answer
- perpendicular to each other
Explanation:
Light consists of electric and magnetic field that are perpendicular 90° to each other.
APPOACH by example
Electric field inside plates. The magnetic field this given rise to via the displacement current is along the perimeter of the circle parallel to capauatates plates.
So B and E are perpendicular in this case.
View full question & answer→Question 711 Mark
A charged particle oscillates about its mean equilibrium position with a frequency of $10^9 \ Hz.$ The electromagnetic waves produced$:$
AnswerHere we are given the frequency by which the charged particles oscillates about its mean equilibrium position, it is equal to $10^9 \ Hz.$ The frequency of electromagnetic waves produced by a charged particle is equal to the frequency by which it oscillates about its mean equilibrium position.
So, frequency of electromagnetic waves produced by the charged particle is $v = 10^9 \ Hz.$
Wavelength $\lambda=\frac{\text{c}}{\text{v}}=\frac{3\times10^8}{10^9}=0.3\text{m}$
The frequency of $10^9 \ Hz$ falls in the region of radiowaves.
View full question & answer→Question 721 Mark
An electromagnetic wave is propagating along Y-axis. Then.
Answer
- oscillating electric field is along Z-axis and oscillating magnetic field is along X-axis
Explanation:
electromagnetic radiation consists of
electromagnetic waves, which are synchronized oscillations of electric and magnetic fields that propagate at the speed of light through a vaccum. The oscillations of the two fields are perpendicular to each other and perpendicular to the direction of energy and wave propagation, forming a transverse wave. so if propogation is along Y-direction ,Electric field will be along X or Z, if it is along Z -direction than Magnetic field has to be in X -direction.
View full question & answer→Question 731 Mark
The electric field intensity produced by the radiations coming from 100W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50W bulb at the same distance is:
Answer
- $\sqrt{2}\text{E}.$
Solution:
We know the electric field intensity on a surface due to incident rediation is,
$\text{I}_\text{av}\propto\text{E}_0^2$
$\frac{\text{P}_\text{av}}{\text{A}}\propto\text{E}_0^2$
Here $\text{P}_\text{av}\propto\text{E}_0^2$ [$\because$ A is same in both cases]
We know that, $\text{E}_0\propto\sqrt{\text{P}_\text{av}}$
$\therefore\ \frac{(\text{E}_0)_1}{(\text{E}_0)_1}=\sqrt{\frac{(\text{P}_\text{av})_1}{(\text{P}_\text{av})_2}}\ .....(\text{i})$
$\Rightarrow\ \frac{\text{E}}{(\text{E}_0)_2}=\sqrt{\frac{1000}{5}}$
$(\text{E}_0)_2=\frac{\text{E}}{\sqrt{2}}$
Nowa according to question, P' = 50W, P = 100W
$\therefore$ Putting these value in Eq. (i), we get
$\frac{\text{E}'}{\text{E}}=\frac{50}{100}\Rightarrow\ \frac{\text{E}'}{\text{E}}=\frac{1}{2}\Rightarrow\ \text{E}'=\frac{\text{E}}{2}$ View full question & answer→Question 741 Mark
Which among the following is an application of microwaves?
Answer
- Ovens
Explanation:
Microwave ovens are an application of microwaves. In microwave ovens, the frequency of microwave produced is matched with the natural frequency of water molecules so that resonance occurs and water molecules in the material vibrate at the higher amplitude and transfer energy to nearby food molecules, results in heating the food.
View full question & answer→Question 751 Mark
Generation, propagation and detection of electromagnetic waves is the basis of:
Answer
- Radio and television
Explanation:
The communication and broadcasting following the base on generation, propagation, and detection of electromagnetic waves.
The electromagnetic spectrum describes a different range of electromagnetic waves. These EM waves are a special type of wave that can travel without a medium.
Electromagnetic waves are named like this due to the fact that they have both an electric and a magnetic component. In a vacuum, EM waves always travel at the same speed i.e. the speed of light. So, other EM waves besides light are infrared, ultraviolet, radio waves, and microwaves.
Therefore radio and television both are based on EM wave properties. Other options like lasers, reactors, and computers are not guided by EM waves.
View full question & answer→Question 761 Mark
Which of the following is used to investigate the structure of solids?
Answer
- X-Rays
Explanation:
X-Rays are used to investigate the structure of solids.
View full question & answer→Question 771 Mark
If a source is transmitting electro$-$magnetic waves of frequency $8.196\times 10^6 \ Hz,$ then the wavelength of the electro$-$magnetic waves transmitted from the source will be$:$
AnswerGiven, frequency of $EM$ waves
$v = 8.196 \times 10^6Hz$
velocity of $EM$ waves $(v) = 3 \times 10^8m/s$
Wavelength of $EM$ waves $\lambda=\frac{\text{v}}{\text{v}}$
$=\frac{3 \times 10^8}{8.196 \times 10^6}$
$= 36.60m$
$= 3660\ cm.$
View full question & answer→Question 781 Mark
When light propagates in vacuum there is an electric field and a magnetic field. These fields:
Answer
- Have zero average value.
- Are perpendicular to the direction of propagation of light.
- Are mutually perpendicular.
Explanation:
Light is an electromagnetic wave that propagates through its electric and magnetic field vectors, which are mutually perpendicular to each other, as well as to the direction of propagation of light. The average value of both the fields is zero.
View full question & answer→Question 791 Mark
An electromagnetic wave propagating along north has its electric field vector upwards. Its magnetic field vector point towards.
Answer
- East
Explanation:
Electric field and magnetic field vectors for an electromagnetic wave are cross - field vectors.
So, the direction of an electromagnetic wave is given by the product of electric field vector and magnetic field vector.
According to the question, electric field vector is directed upwards and EM wave is directed towards North. So, according to the right - hand thumb rule, the magnetic field vector points towards the East.
View full question & answer→Question 801 Mark
The part of the spectrum of the electromagnetic radiation used to cook food is then:
Answer
- microwaves
Explanation:
Microwaves are used to cook food. Microwave oven is a domestic application of these waves.
View full question & answer→Question 811 Mark
The propagation constant of a photon of wavelength $6284 \ A^\circ .$
AnswerThe propagation constant can be written as
$\text{K}=\frac{2pi}{\lambda}$
$=\frac{60284}{6284\times10^{-8}}$
$=10^5\text{cm}^{-1}$
View full question & answer→Question 821 Mark
The oscillating electric and magnetic vectors of an electromagnetic wave are oriented along:
Answer
- Mutually perpendicular directions and are in phase
Explanation:
$\overrightarrow{E}$ and $\overrightarrow{B}$ are mutually perpendicular to each other and are in phase i.e., they become zero and minimum at the same place and at the same time. View full question & answer→Question 831 Mark
When light propagates in vaccum there is an electric field and a magnetic field. Which of the following is not true about these field?
Answer
- They are constant in time
Explanation:
They vary with time following a wave function (sinuosoidal) and average value of these function is zero and also we can see in figure they are mutually perpendicular and also perpendicular to direction of propagation.
View full question & answer→Question 841 Mark
In electromagnetic spectrum, the frequencies $\gamma-$rays$, X-$rays and ultraviolet rays are denoted by $n_1, n_2$ and $n_3$ respectively then$:$
AnswerFrom electromagnetic spectrum, frequencies of $\gamma-$rays is greater than frequency of $X-$rays. Frequency of Xrays is greater than frequency of ultraviolet rays.
View full question & answer→Question 851 Mark
A metal block is exposed to beams of X-ray of different wavelength. X-rays of which wavelength penetrate most?
Answer
- $2\mathring{\text{A}}$
Explanation:
Penetrating power is greater for lower wavelength. View full question & answer→Question 861 Mark
If the wavelength of electromagnetic radiation is doubled, what will happen to the energy of photons?
Answer
- Halved
Explanation:
Energy of a photon,
$\text{E} = \text{hv} = \frac {\text{hc}}{\lambda}.$
$\text{E}\propto\frac{1}{\lambda}.$
When the wavelength of electromagnetic radiation is doubled, the energy of the photons is halved. View full question & answer→Question 871 Mark
A plane electromagnetic wave is incident on a material surface. The wave delivers momentum p and energy E.
Answer
- $\text{p}\neq0,\text{ E}\neq0$
Explanation:
When an electromagnetic wave strikes a material surface, it transports the momentum, as well as the energy, to the surface. The striking electromagnetic wave exerts pressure on the surface. The total energy transferred to the surface by the electromagnetic wave is given by $\text{E}=\text{pc}$ Therefore, $\text{p}\neq0,\text{ E}\neq0$ View full question & answer→Question 881 Mark
Answer
- continuous when electric field is changing in the circuit
View full question & answer→Question 891 Mark
The frequency of electromagnetic wave in free space is 2 MHz. When it passes through a region of relative permittivity $\epsilon_\text{r}=4.0,$ then its wave length __________ & frequency ______________
Answer
- Becomes half, remains constant
View full question & answer→Question 901 Mark
In electromagnetic wave, according to Maxwell, changing electric field gives.
AnswerBy Maxwell
$\text{I}_\text{d}=\frac{\epsilon\text{dE}}{\text{dt}}$
$dE$ is electric field
$I_d$ is displacement current per unit area.
Hence changing electric field gives displacement current.
View full question & answer→Question 911 Mark
The ratio of contributions made by the magnetic field and electric field components to the intensity of an EM wave is:
Answer
- 1:1
Explanation:
The ratio of contributions made by the magnetic field and electric field components to the intensity of an EM wave is 1:1.
View full question & answer→Question 921 Mark
Which of the following has zero average value in a plane electromagnetic wave?
Answer
- Both (b) and (©)
Explanation:
The average of $\sin\theta$ and $\cos\theta$ for whole cycle is is zero.
Step 1: Analyzing the average value of Kinetic energy.
Kinetic Energy is always a positive quantity, therefore its average will also be a positive quantity.
Step 2: Finding the average of electric and the magnetic field.
The equations for the electric field and the magnetic field are given as View full question & answer→Question 931 Mark
An electromagnetic wave travelling along z-axis is given as: $\text{E}=\text{E}_0\cos(\text{kz}-\omega\text{t})$. Choose the correct options from the following;
Answer
- The associated magnetic field is given as $\text{B}=\frac{1}{\text{c}}\text{k}\times\text{E}=\frac{1}{\omega}(\hat{\text{k}}\times\text{E})$.
- The electromagnetic field can be written in terms of the associated magnetic field as $\text{E}=\text{c}(\text{B}\times\hat{\text{k}})$.
- $\hat{\text{k}}.\text{E}=0,\hat{\text{k}}.\text{B}=0.$
Solution:
- The direction of propagation of an eletromagnetic wave is always along the direction of vector product $\vec{\text{E}}\times\vec{\text{B}}$. Refer to Figure.
$\vec{\text{B}}=\text{B}\hat{\text{j}}=\text{B}(\hat{\text{k}}\times\hat{\text{i}})=\frac{\text{E}}{\text{C}}(\hat{\text{k}}\times\hat{\text{i}})$
$=\frac{1}{\text{c}}[\text{k}\times\text{E}\hat{\text{i}}]=\frac{1}{\text{c}}[\hat{\text{k}}\times\vec{\text{E}}]\bigg(\text{as}\frac{\text{E}}{\text{B}}=\text{c}\bigg)$
- $\vec{\text{E}}=\text{E}\hat{\text{i}}=\text{cB}(\hat{\text{j}}\times\hat{\text{k}})=\text{c}(\text{B}\hat{\text{j}}\times\text{k})=\text{c}(\vec{\text{B}}\times\hat{\text{k}})$
- $\hat{\text{k}}.\vec{\text{E}}=\hat{\text{k}}.(\text{E}\hat{\text{i}})=0,\vec{\text{k}}.\vec{\text{B}}=\vec{\text{k}}.(\text{B}\hat{\text{j}})=0$
- $\hat{\text{k}}\times\vec{\text{E}}=\hat{\text{k}}\times(\text{E}\hat{\text{i}})=\text{E}(\hat{\text{k}}\times\hat{\text{i}})=\text{E}\hat{\text{j}}$ and $\hat{\text{k}}\times\vec{\text{B}}=\hat{\text{k}}\times(\text{B}\hat{\text{j}})=\text{B}(\hat{\text{k}}\times\hat{\text{j}})=-\text{B}\hat{\text{i}}$.
View full question & answer→Question 941 Mark
An electromagnetic wave going through vacuum is described by $\text{E}=\text{E}_0\sin(\text{kx}-\omega\text{t}),\text{ B}=\text{B}_0\sin(\text{kx}-\omega\text{t})$ Then:
AnswerThe relation between $E_0$ and $B_0$ id given by $\frac{\text{E}_0}{\text{B}_0}=\text{c}\ ....(\text{i})$
Here, $c =$ Speed of the electromagnetic wave,
The relation between $\omega ($the angular frequency$)$ and $k($wave number$),$
$\frac{\omega}{\text{k}}=\text{c}\ ...(ii)$
Therefore, from $(i)$ and $(ii),$ we get
$\frac{\text{E}_0}{\text{B}_0}=\frac{\omega}{\text{k}}=\text{c}$
$\text{E}_0\text{k}=\text{B}_0\omega$
View full question & answer→Question 951 Mark
The electric field intensity at a point in vacuum is equal to:
Answer
- Force a unit positive charge would experience there.
Explanation:
The electric field intensity at a point in a vacuum is equal to force experienced by a unit positive charge placed at that point.
View full question & answer→Question 961 Mark
An electromagnetic wave radiates outwards from a dipole antenna, with $E_0$ as the amplitude of its electric field vector. The electric field $B_0$ which transports significant energy from the source falls off as$:$
AnswerAn antenna that produces the Electromagnetic wave are radiated outwards. The amplitude of electric field vector $(E_0).$ This electric field vector transports the energy from the source through the medium.
The electric field intensity of the wave from the source at a distance is inversely proportional to the distance between the source and the point. $\text{E}_0=\frac{1}{\text{r}}$
View full question & answer→Question 971 Mark
Huygens' principle of secondary wavelets may be used to:
Answer
- Find the new position of a wavefront.
- Explain Snell's law.
Explanation:
Huygen's wave theory explains the origin of points for the new wavefront proceeding successively. It also explains the variation in speed of light on moving from one medium to another, i.e. it proves Snell's Law.
View full question & answer→Question 981 Mark
A charged particle oscillates about its mean equilibrium position with a frequency of $10^9\ Hz.$ The frequency of electromagnetic waves produced by the oscillator is$:$
AnswerThe frequency of the electromagnetic wave is same as that of oscillating charged particle about its equilibrium position, which is $10^9\ Hz.$
View full question & answer→Question 991 Mark
According to Maxwell's hypothesis, changing of electric filed give rise to.
Answer
- magnetic field
Explanation:
According to Maxwell's hypothesis, changing of electric field gives rise to Magnetic field.
We know that F = qE,, where F is force and E is electric field.
We can relate magnetic field and force by F = qvB, where v is velocity and B is the magnetic field.
Therefore we can obtain magnetic field by changing electric field.
View full question & answer→Question 1001 Mark
Two waves having same velocity enter electric and magnetic fields respectively. If $\lambda_1$ and $\lambda_2$ are their wavelengths as they move in the fields, then.
Answer
- $\lambda_1$ and $\lambda_2$ are variable
Explanation:
Velocity of a wave is given by:
$\text{v}=\frac{\text{E}}{\text{B}}$
Hence wave velocity change in both the cases.
Frequency of the wave remains the same.
Using $\text{v}=\text{f}\lambda,$ it can be concluded that both $\lambda_1$ and $\lambda_2$ are variable. View full question & answer→Question 1011 Mark
When an electromagnetic wave enters an ionised layer of earth’s atmosphere present in ionosphere:
Answer
- The electron cloud will oscillate in the electric field of wave with a phase retardation of 90° for a sinusoidal electromagnetic wave.
View full question & answer→Question 1021 Mark
For television broadcasting the frequency employed is normally:
View full question & answer→Question 1031 Mark
According to Maxwell's hypothesis, a changing electric field gives rise to.
View full question & answer→Question 1041 Mark
If the wavelength of red light in air is $7500 A,$ then the frequency of light in air is.
AnswerVelocity of wave $=$ wavelength $\times$ frequency
$\text{v}=3\times10^8\frac{\text{m}}{\text{s}}$
$\lambda=7500\text{A}$
$=7500\times10^{-10}\text{m}$
$\text{f}=\frac{3\times10^8}{7500\times10^{-10}}$
$=4\times10^{14}\text{Hz}$
View full question & answer→Question 1051 Mark
An electromagnetic wave going through vacuum is described by $\text{E}=\text{E}_0\sin(\text{kx}-\omega\text{t});\text{B}=\text{B}_0\sin(\text{kx}-\omega\text{t}).$ Which of the following equation is true?
Answer
- $\text{E}_0\text{k}=\text{B}_0\omega$
Explanation:
$\frac{\text{E}_0}{\text{B}_0}=\text{c},$ also $\frac{2\pi}{\lambda}$ and $\omega=2\pi\text{v}.$
$\Rightarrow\frac{\text{E}_0}{\text{B}_0}=\frac{\omega}{\text{k}}$
$\text{E}_0\text{k}=\text{B}_0\omega$ View full question & answer→Question 1061 Mark
X−ray falling on a material.
Answer
- Transfer energy to it
Explanation:
The emitted X-rays transfer energy to the material on which it is falling.
View full question & answer→Question 1071 Mark
If $\overrightarrow{\text{E}}$ and $\overrightarrow{\text{B}}$ are the electric and magnetic field vectors of electromagnetic waves then the direction of propagation of electromagnetic wave is along the direction of:
Answer
- $\overrightarrow{\text{E}}\times\overrightarrow{\text{B}}$
Explanation:
The direction of propagation of electromagnetic wave is perpendicular to the variation of electric field $\overrightarrow{\text{E}}$ as well as to the magnetic field $\overrightarrow{\text{B}}$ View full question & answer→Question 1081 Mark
Which of the following conclusion can be drawn from the result $\oint\overline{\text{B}}\cdot\text{d}\overline{\text{A}}=0$
Answer
- Magnetic monopole cannot exist
Explanation:
Flux of certain closed surface is zero and so it tells that net magnetic charge is equal to zero. This is possible when there are two equal and opposite poles.
View full question & answer→Question 1091 Mark
Beyond which frequency, the ionosphere bands any incident electromagnetic radiation but do not reflect it back towards the earth?
Answer
- 40MHz
Explanation:
The ionosphere can reflect electromagnetic waves of frequency less than 40MHz but not of frequency more than 40MHz.
View full question & answer→Question 1101 Mark
The ratio of amplitude of a magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
Answer
- Reciprocal of speed of light in vacuum
Explanation:
Both electric field and magnetic field are vector quantities.
They both are components of electromagnetic waves.
We know that,
$\text{c}=\frac{\text{E}_0}{\text{B}_0}$
$\frac{\text{B}_0}{\text{E}_0}=\frac{1}{\text{c}}$
View full question & answer→Question 1111 Mark
Waves in decreasing order of their wavelength are:
Answer
- radio waves, infrared rays, visible rays, X-rays.
View full question & answer→Question 1121 Mark
The displacement current flows in the dielectric of a capacitor when the potential difference across its plates.
Answer
- is increasing with time
Explanation:
According to Maxwell's hypothesis, a displacement current will flow through a capacitor when the potential difference across its plates is varying. Thus a varying electric field will exist between the plates and this displacement current is same in magnitude to the current flowing in outer circuit. When a D.C voltage applied across its plates, constant voltage appears across its plates and so there will be no displacement current flowing through the capacitor. Thus the displacement current will flow when the potential is increasing with time.
View full question & answer→Question 1131 Mark
Which is the frequency range of gamma rays from the following?
AnswerThe frequency range of Gamma rays is $3 \times 10^{18}$ to $5 \times 10^{22 }Hz.$ These rays have a wavelength of $6 \times 10^{-13}$ to $10^{-10}m.$ Gamma rays are produced in nuclear reactions and are also emitted by radioactive nuclei.
View full question & answer→Question 1141 Mark
When light propagates in vacuum there is an electric field and a magnetic field. These fields.
Answer
- have zero average value
- are perpendicular to the direction of propagation of light.
- are mutually perpendicular
Explanation:
When light propagates in vacuum there is an electric field and a magnetic field which has zero average value. They are perpendicular to each other and also perpendicular to the direction of the propagation of light.
View full question & answer→Question 1151 Mark
On what basis is the classification of electromagnetic waves done?
Answer
- Electromagnetic spectrum
Explanation:
The classification of electromagnetic waves done according to the frequency called the electromagnetic spectrum. The basic difference various type of electromagnetic waves lies in their wavelength or frequency since all of them travel through vacuum at the same speed and also, the waves differ in their mode of interaction with matter.
View full question & answer→Question 1161 Mark
Wavelength of, monochromatic light is $5000A^\circ.$ It's wave number is$:$
AnswerWave number $=\frac{1}{\text{wavelength}}$
$=\frac{1}{5000\times10^{-10}}$
$=2\times10^6\text{m}^{-1}$
View full question & answer→Question 1171 Mark
Ultraviolet spectrum can be studied by using a:
View full question & answer→Question 1181 Mark
The amplitude of the sinusoidally oscillating electric field of a plane wave is $60\ v/m.$ Then the amplitude of the magnetic field is$:$
AnswerGiven: Electric field $= 60\ v/m$
$C = 3\times 10^8\ m/s^2$
To find: Magnetic field
Solution$:$
We know, $\text{C}=\frac{\text{E}_0}{\text{B}_0}$
Therefore, $\text{B}_0=\frac{\text{E}_0}{\text{C}}$
$\frac{60}{3\times10^8}=2\times10^7\text{T}$
View full question & answer→Question 1191 Mark
An electron oscillating with a frequency of $3 \times 10^6 Hz,$ would generate:
View full question & answer→Question 1201 Mark
Which one of the following is the primary effect of UV radiation caused due to depletion of ozone layer?
Answer
- Skin cancer
Explanation:
The ozone layer prevents most harmful UV wavelengths of ultraviolet light (UV light) from passing through the Earth's atmosphere. These wavelengths cause skin cancer, sunburn and cataracts, which were projected to increase dramatically as a result of thinning ozone, as well as harming plants and animals.
View full question & answer→Question 1211 Mark
Displacement current is continuous:
Answer
- when electric field is changing in the circuit
Explanation:
Displacement current is a quantity appearing in Maxwell's equations that is defined in terms of the rate of change of electric displacement field.
When electric field is changing with time continuously, the displacement current is constant.
View full question & answer→Question 1221 Mark
If a variable frequency ac source is connected to a capacitor then with decrease in frequency the displacement current will:
View full question & answer→Question 1231 Mark
The absorption of radio waves by the atmosphere depends upon:
View full question & answer→Question 1241 Mark
In Maxwell's velocity distribution curve area under the graph:
Answer
- Remains same at all temperature.
Explanation:
Area under the Maxwell's velocity distribution curve gives the number of particles. Since number of particles remains the same at all the temperatures, so the area under the curve also remains the same at all temperature.
View full question & answer→Question 1251 Mark
In an electromagnetic wave, the electric magnetising fields are $\frac{100\text{V}}{\text{m}}$ and $\frac{0.265\text{A}}{\text{m}}$ The maximum energy flow is?
AnswerMaximum rate of energy flow, $S = E_0 \times H_0$
Given, $\text{E}_0=\frac{100\text{V}}{\text{m}},\text{H}_0=\frac{0.265\text{A}}{\text{m}}$
$\therefore\text{S}=100\times0.265=\frac{26.5\text{W}}{\text{m}^2}$
View full question & answer→Question 1261 Mark
The figure here gives the electric field of an EM wave at a certain poiunt and a certain instrant. the wave is transporting energy in the negative z direction. what is tha direction of the magnetic field of the wave at that point and instant.

Answer
- Towards +X direction
Explanation:
The direction of EM wave is given by the direction of $\overrightarrow{\text{E}}\times\overrightarrow{\text{B}}$ View full question & answer→Question 1271 Mark
The speeds of microwaves, infrared waves, and ultraviolet waves are $V_m, V_i,$ and $V_u$ respectively. Identify the correct combination showing the different waves in vacuum.
AnswerThe correct combination is $➔ Vm = Vi = Vu.$ This is because, in vacuum, all the electromagnetic waves in question will travel at the same speed. The speed with which they travel in vacuum is the speed of light. $(c = 3 \times 108\ m/s).$
View full question & answer→Question 1281 Mark
Which of the following electromagnetic waves is used in medicine to destroy cancer cells?
Answer
- Gamma rays
Explanation:
Gamma rays has property to kill cancer cell because the energy released by gamma ray is perfect to kill and leave out the healthy ones.
View full question & answer→Question 1291 Mark
Choose the correct answer from alternatives given.
If $\overrightarrow{\text{E}}$ and $\overrightarrow{\text{B}}$ represent electric and magnetic field vectors of an electromagnetic wave, the direction of propagation of the wave is along.
Answer
- $\overrightarrow{\text{E}}\times\overrightarrow{\text{B}}$
Explanation:
Electromagnet waves have electric field as well as magnetic field which are perpendicular to each other and the electromagnetic waves propagate in a direction
which is perpendicular to both the fields.
Thus the propagation vector of EM waves $\overrightarrow{\text{k}}=\overrightarrow{\text{E}}\times\overrightarrow{\text{B}}$ View full question & answer→Question 1301 Mark
Assume you are sitting in sun for $2.5$ hours. The area of your body exposed normally to sun rays $1.3m^2.$ The intensity of sun rays is $\frac{1.1 \ \text{Kilowatt}}{\text{m}^2}$ If your body completely absorbs the sun rays then the momentum transferred to your body will be $($in $\ Kg - \frac{\text{m}}{\text{s}}):$
AnswerPower $=$ intensity $\times$ area
Intensity and area are given,
Power $= 1.3 \times 1.1 \ KW$
Energy $=$ power $\times$ time
Time is $2.5\ hr$
Energy $= 1300 \times 1.1 \times 2.5 \times 3600J$
$= 12870000J$
$\text{Momentum}=\frac{\text{energy}}{\text{c}}$
$=\frac{12870000}{3\times10^8}$
$=0.043$
View full question & answer→Question 1311 Mark
In the propagation of electromagnetic waves the angle between the direction of propagation and the plane of vibration is ________
Answer
- $\frac{\pi}{2}$
Explanation:
Axis of propagation always lie perpendicular to the plane of vibrations, therefor angle between them is $\frac{\pi}{2}$ View full question & answer→Question 1321 Mark
Which of the following statement is false for the properties of em waves?
Answer
- Both electric and magnetic field vectors are parallel to each and perpendicular to the direction of propagation of wave.
View full question & answer→Question 1331 Mark
Which of the following statement is false for the properties of electromagnetic waves?
Answer
- Both electric and magnetic field vectors are parallel to each other and perpendicular to the direction of propagation of wave.
View full question & answer→Question 1341 Mark
Calculate the wavelength of electromagnetic waves of frequency 300MHz.
View full question & answer→Question 1351 Mark
A compass needle is placed in the gap of a parallel plate capacitor. The capacitor is connected to a battery through a resistance. The compass needle:
Answer
- Deflects and gradually comes to the original position in a time that is large compared to the time constant.
Explanation:
The compass needle deflects due to the presence of the magnetic field. Inside the capacitor, a magnetic field is produced when there is a changing electric field inside it. As the capacitor is connected across the battery, the charge on its plates at a certain time tis given by,
$\text{Q}=\text{CV}\Big(1-\text{e}^{-\tau/\text{RC}}\Big),$
Q = Charge developed on the plates of the capacitor.
R = Resistance of the resistor connected in series with the capacitor.
C = Capacitance of the capacitor.
V = Potential difference of the battery.
The time constant of the capacitor is given, $\tau=\text{RC}$
The capacitor keeps on charging up to the time $\tau$. The development of charge on the plates will be gradual after $\tau=\text{RC}$ The change in electric field will be up to the time the charge is developing on the plates of the capacitor. Thus, the compass needle deflects and gradually comes to the original position in a time that is large compared to the time constant. View full question & answer→Question 1361 Mark
If E and B represent electric and magnetic field vectors of the electromagnetic wave, the direction of propagation of electromagnetic wave is along,
Answer
- E × B.
Solution:
Key concept: A changing electric field produces a changing magnetic field and vice versa which gives rise to a transverse wave known as electromagnetic wave. The time varying electric and magnetic field are mutually perpendicular to each other and also perpendicular to the direction of propagation of this wave. The electric vector is responsible for the optical effects of an EM wave and is called the light vector.

The direction of propagation of electromagnetic wave is perpendicular to both electric field vector $(\vec{\text{E}})$ and $\vec{\text{B}}$ magnetic field vector B, i.e., in the direction of $\vec{\text{E}}\times\vec{\text{B}}$.
Here, elecromagnetic wave is along the z-direction which is given by the cross product of E and B. View full question & answer→Question 1371 Mark
The period of the wave will be.
Answer
- $0.025\mu\text{s}$
Explanation:
Time period, $\text{T}=\frac{1}{\text{v}}$
$\text{T}=\frac{1}{40\times10^6}$
$\Rightarrow\text{T}=0.25\mu\text{s}$ View full question & answer→Question 1381 Mark
For which frequency of light, the human eye is most sensitive?
AnswerHuman eye is sensitive to light of wavelength $➔ \lambda = 5550$ angstrom.
So its frequency is $\text{v}=\frac{\text{c}}{\lambda}$
$\text{v} =\frac{5550}{3 \times 10^8} \times 10^{-10}$
$v = 5.405 \times 10^{14} Hz$
View full question & answer→Question 1391 Mark
Which of the following cannot be polarized?
Answer
- Ultrasonic waves
Explanation:
All the longitudinal waves like sound etc cannot be polarized because the motion of the particles is already in one dimension that is the direction of propagation of wave.
Thus all the transverse waves like electromagnetic waves can be polarized.
Thus, (B) Ultrasonic waves being sound waves having frequency greater than 20kHz but being longitudinal in nature cannot be polarized
View full question & answer→Question 1401 Mark
If the directions of electric and magnetic field vectors of a plane electromagnetic wave are along positive y-direction and positive z-direction respectively, then the direction of propagation of the wave is along:
Answer
- positive x-direction
Explanation:
e = E × B, direction of propagation is always perpendicular to plane of E and B. It will be positive in x-direction.
View full question & answer→Question 1411 Mark
A plane electromagnetic wave propagating along $x$ direction can have the following pairs of $E$ and $B.$
AnswerThe direction of propagation of electromagnetic wave is perpendicular to both electric field vector $(\vec{\text{E}})$ and $(\vec{\text{B}})$magntic field vector $B,$ i.e., in the direction of $\vec{\text{E}}\times\vec{\text{B}}$.
Here in the question electromagnetic wave is propagating along $x-$direction.
So, electro and magnetic field vectors should have either $y-$direction of $2-$direction.
View full question & answer→Question 1421 Mark
Radiation pressure on any surface:
Answer
- Is dependent on nature of surface and intensity of light used
Explanation:
Radiation pressure is given by $\text{P}_\text{R}=\frac{(1+\alpha)\text{I}}{\text{C}}$
where α is the coefficient of reflection of the surface.
For completely reflecting surface $\alpha=1$
For completely absorbing surface $\alpha=0$
So, radiation pressure depends on the nature of surface on which the light is falling but independent of wavelength of light falling. View full question & answer→Question 1431 Mark
An electromagnetic waves can be produced, when charge is:
Answer
- both (b) and (c)
Explanation:
An accelerated charge is the source of electromagnetic waves (EMWs). When the charge is in a circular motion, the direction of its velocity continuously changes and thus it is in accelerated motion and produces EMWs.
A charge falling in an electric field is accelerated by the electric force and thus produces EMWs.
View full question & answer→Question 1441 Mark
The displacement current was first populated by.
Answer
- Maxwell
Explanation:
In electromagnetism, displacement current is a quantity appearing in Maxwell's equations that is defined in terms of the rate of change of electric displacement field.
View full question & answer→Question 1451 Mark
Speed of electromagnetic waves is the same:
Answer
- For all intensities.
Explanation:
For any given medium, the speed (c) of an electromagnetic wave is given by,
$\text{C}=\text{v}\lambda$
Where,
V = Frequency of the electromagnetic wave.
$\lambda=$ wavelength of the electromagnetic wave.
As the frequency and wavelength are changed, the speed of the electromagnetic wave changes. So, the speed of an electromagnetic wave is not same for all wavelengths and all frequencies in any medium. The velocity of an electromagnetic wave changes with change in medium. Also, the speed of an electromagnetic wave is same for all the intensities in any medium. View full question & answer→Question 1461 Mark
Consider an electromagnetic wave propagating in vacuum. Choose the correct statement:
Answer
- For an electromagnetic wave propagating in +x direction the electric field is $\overrightarrow{\text{E}}=\frac{1}{\sqrt{2}}\text{E}_\text{yz}(\text{x,t})(\hat{\text{y}}-\hat{\text{z}})$ and the magnetic field is $\overrightarrow{\text{B}}=\frac{1}{\sqrt{2}}\text{E}_\text{yz}(\text{x,t})(\hat{\text{y}}+\hat{\text{z}})$
Explanation:
Electromagnetic waves travel in the direction perpendicular to electric as well as magnetic field. Cross product of electric and magnetic field should give the direction of electromagnetic wave. View full question & answer→Question 1471 Mark
The EM waves when travel into different media gets:
View full question & answer→Question 1481 Mark
An electromagnetic radiation has an energy of 13.2 keV. Then the radiation belongs to the region of.
View full question & answer→Question 1491 Mark
Which of the following have zero average value in a plane electromagnetic wave?
Answer
- Electric field.
- Magnetic field.
Explanation:
In a plane electromagnetic wave, the electric and the magnetic fields oscillate sinusoidally. For an electromagnetic wave propagating in the z-direction, the electric and magnetic fields are given by,
$\text{E}_\text{x}=\text{E}_0\sin(\text{kz}-\omega\text{t})$
$\text{B}_\text{y}=\text{B}_0\sin(\text{kz}-\omega\text{t})$
These are sinusoidal functions. Therefore, for a fixed value of z. the average value of the electric and magnetic fields are zero. View full question & answer→Question 1501 Mark
The value of electric field in an electromagnetic wave originating from a point source of light at a distance of 10 meter is $\text{E}=\frac{500\text{Volt}}{\text{m}}$ The electric field at a distance of 5 meter will be.
Answer
- $\frac{2000\text{Volt}}{\text{meter}}$
Explanation:
As we know, $\text{E}\propto\text{R}^{-2}$
Therefore, $\text{E}(\text{R}=5)=\frac{500}{10^{-2}}5^{-2}=\frac{2000\text{V}}{\text{m}}$ View full question & answer→Question 1511 Mark
Monica wanted to take photographs of a monument. But since the surrounding is filled with smoke, she is not able to take good photos. Which one of the following electromagnetic waves can be used in this situation to help Monica?
Answer
- Infrared waves
Explanation:
Infrared waves can be used to take photographs during conditions of smoke, fog, etc. as these waves are scattered less than visible rays and hence travel longer distances through the atmosphere. So, using infrared waves can help Monica out.
View full question & answer→Question 1521 Mark
Is the ratio of frequencies of UV rays and IR rays in the glass more than, less than or equal to 1?
Answer
- More than 1
Explanation:
The ratio of frequencies of UV rays and IR rays in the glass is more than 1. This is because the frequency of UV rays is greater than that of infrared rays. This situation is applicable in glass or vacuum or air.
View full question & answer→Question 1531 Mark
The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is $B_{0 }= 510nT.$ The amplitude of the electric field part of the wave is:
AnswerGiven,
$B_0 = 510nT$
$c = 3\times 10^8\ m/s$
The magnitude of electric field is given by
$E_0 = B_{0}c$
$E_0 = 510\times 10^{−9}\times 3\times 10^8$
$E_{0 }= 153 N C^{−1}$
View full question & answer→Question 1541 Mark
In an electromagnetic wave.
Answer
- Power is transmitted in a direction perpendicular to both the field
Explanation:
For electromagnetic waves E and B are always perpendicular to each other and perpendicular to the direction of propagation. The direction of propagation is the direction of E × B.
The direction of propagation of the wave is the direction of propagation of its energy and power.
View full question & answer→Question 1551 Mark
Microwaves are electromagnetic waves with frequency in the range of:
View full question & answer→Question 1561 Mark
An $EM$ wave radiates outwards from a dipole antenna, with $E_0$ as the amplitude of its electric field vector. The electric field $E_0$ which transports significant energy from the source falls off as$:$
AnswerA diode antenna radiates the electromagnetic waves outwards. The amplitude of electric field vector $(E_0)$ which transports significant energy from the source falls intensity inversely as the distance $(r)$ from the antenna,
i.e., $\text{E}_0\propto\frac{1}{\text{r}}$.
View full question & answer→Question 1571 Mark
In Thomson's experiment to measure e/ m of electron, the electric and the magnetic fields are.
Answer
- Perpendicular to each other
Explanation:
The experimental set up of Thomson's experiment is shown in figure,
According to this figure, the electric field is applied between two horizontal parallel plates, this field is directed in downward direction.
The cross in figure shows the magnetic field is directed inside the paper. Therefore, both the fields are perpendicular to each other.
View full question & answer→Question 1581 Mark
What is the ratio of the speed of infrared and ultraviolet rays in a vacuum?
Answer
- 1
Explanation:
Ratio = 1 because the speed of an electromagnetic wave in vacuum is independent of its wavelength or frequency. Therefore, the ratio of speed of infrared and ultraviolet rays in a vacuum is one.
View full question & answer→Question 1591 Mark
Which of the following statement(s) is/ are correct?
Answer
- Conduction current obeys Ohm's law whereas displacement current does not.
Explanation:
Displacement current is the current that occurs due to charging electric field introduced by maxwell. It depends on the frequency of electric field while conduction current follows ohms law, requires medium displacement.Current doesnot follow ohms law nor require medium.
View full question & answer→Question 1601 Mark
Instantaneous displacement current 1A in the space between the parallel plates of $1\mu\text{F}$ capacitor can be established by changing the potential difference at the rate of:
Answer
- $\frac{10^6\text{V}}{\text{s}}$
Explanation:
In a capacitor of capacitance C,
$\text{V}=\frac{\text{q}}{\text{C}}$
$\Rightarrow\frac{\text{dV}}{\text{dt}}=\frac{\text{i}}{\text{C}}=\frac{1\text{A}}{1\mu\text{F}}=\frac{10^6\text{V}}{\text{s}}$ View full question & answer→Question 1611 Mark
One requires $11\ eV$ of energy to dissociate a carbon monoxide molecule into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in:
AnswerHere it is given, the energy required to dissociate a carbon monoxide molecule into catbon and oxygon atoms is $E = 11\ eV$
We know that$, E = hf = 6.62 \times 10^{-34}J-s$
$f =$ frequency
$\Rightarrow 11\ eV = hf$
$\text{f}=\frac{11\times1.6\times10^{-19}}{6.62\times10^{-34}}=2.65\times10^{15}\text{Hz}$
This frequency radiation belongs to ultraviolet region.
Important point:

View full question & answer→Question 1621 Mark
Which of the following waves have a maximum frequency?
Answer
- Gamma rays
Explanation:
Gamma rays have a maximum frequency.
View full question & answer→Question 1631 Mark
A free electron is placed in the path of a plane electromagnetic wave. The electron will start moving:
Answer
- Along the electric field.
Explanation:
As the electron is at rest initially, only the electric field will exert force on it. There will be no magnetic force on the electron in the stating. Hence, the electron will start moving along the electric field.
View full question & answer→Question 1641 Mark
Pick out the electromagnetic wave which is highly harmful to humans.
Answer
- Ultraviolet Rays
Explanation:
Ultraviolet (UV) radiations in large quantities are highly harmful to humans. These rays in solar radiation on reaching earth are absorbed by the ozone layer in the atmosphere. UV rays are produced by special lamps such as mercury and from arc lamps and by very hot bodies like the sun.
View full question & answer→Question 1651 Mark
Maxwell in his famous equations of electromagnetism introduced the concept of:
View full question & answer→Question 1661 Mark
Choose the correct answer from the alternatives given. Electromagnetic wave consists of periodically oscillating electric and magnetic vectors:
Answer
- In mutually perpendicular planes but vibrating in phase
Explanation:
The Electromagnetic wave consists of the two mutually perpendicular electric and magnetic fields present in the medium and also both being perpendicular to the direction of propagation of the wave. The two fields are in same phase as they obtain their peaks at the same instant.
An electromagnetic wave consists of periodically oscillating electric and the magnetic vector in mutually perpendicular planes but vibrating in phase.

View full question & answer→Question 1671 Mark
What is the full form of UHF?
Answer
- Ultra-high frequency
Explanation:
UHF stands for Ultra high frequency. Cellular phones used radio waves to transmit voice communication in the Ultra high-frequency Band. The UHF band extends from 900 MHz to 5 x 109 Hz or 5000 MHz. Radio waves are produced by oscillating circuits having an inductor and capacitor.
View full question & answer→Question 1681 Mark
The source of electromagnetic waves can be a charge:
Answer
- Moving in a circular orbit.
- falling in an electric field.
Solution:
Key concept:
- An electromagnetic wave can be produced by accelerated or oscillating charge.
- An oscillating charge is accelerating continuously, it will radiate electromagnetic waves continuously.
- Electromagnetic waves are also produced when fast moving electrons are suddenly stopped by a metal target of high atomic number.
Here, in option (b) charge is moving in a circular orbit.
In circular motion, the direction of the motion of charge is changing continuously, thus it is an accelerated motion and this option is correct.
In option (d), the charge is falling in electric field. If a charged particle is moving in electric field it experiences a force or we can say it accelerates. We know an accelerating charge particle radiates electromagnetic waves. Hence option (d) is also correct.
Also, we know that a charge starts accelerating when it falls in an electric field.
Important points:
- In an atom an electron is circulating around the nucleus in a stable orbit, although accelerating does not emit electromagnetic waves; it does so only when it jumps from a higher energy orbit to a lower energy orbit.
- A simple LC oscillator and energy source can produce waves of desired frequency
View full question & answer→Question 1691 Mark
Electromagnetic waves are transverse in nature is evident by.
View full question & answer→Question 1701 Mark
The conduction current is same as displacement current when source is:
View full question & answer→Question 1711 Mark
The pressure exerted by an electromagnetic wave of intensity I$\Big(\frac{\text{watt}}{\text{m}^2}\Big)$ on a non-reflecting surface is : [c is the velocity of light].
Answer
- $\frac{\text{I}}{\text{c}}$
Explanation:
Momentum of a photon
$=\frac{\text{h}}{\lambda}=\frac{\text{h}}{\frac{\text{c}}{\text{v}}}=\frac{\text{hv}}{\text{c}}=\frac{\text{E}}{\text{c}}$
Momentum over unit area
$=\frac{\text{E}}{\text{Ac}}=\frac{\text{I}}{\text{c}}\Big[\text{I}=\frac{\text{E}}{\text{A}}\text{ For wave}\Big]$
Since surface is non reflecting, final momentum of photon = 0, change in momentum $=\frac{\text{I}}{\text{c}}$
So, force per unit area $=\frac{\text{I}}{\text{c}}$
Pressure of radiation $=\frac{\text{I}}{\text{c}}$ View full question & answer→Question 1721 Mark
Maxwell's equation describe the fundamental laws of.
Answer
- both (A) and (B)
Explanation:
Maxwell's equation describe the fundamental laws of electricity and magnetism. His equations describe how electric and magnetic fields are generated and altered by each other and by charges and currents.
View full question & answer→Question 1731 Mark
The electric field for a plane, electomagnetic wave travelling in the +y direction is shown in figure.If the electric field of the wave $\overline{\text{E}}$ is in the Z direction , then the $\overline{\text{B}}$ field is.

Answer
- In the x direction and in phase with the $\overline{\text{E}}$ field
Explanation:
The wave equation for a plane electric wave traveling in the x direction in space is
$\frac{\delta^2\text{E}}{\delta^2\text{y}}=\frac{1}{\text{c}^2}\frac{\delta^2\text{E}}{\delta\text{t}^2}$
with the same form applying to the magnetic field wave in a plane perpendicular the electric field. Both the electric field and the magnetic field are perpendicular to the direction of travel y. View full question & answer→Question 1741 Mark
A parallel plate capacitor is charged to $60\ \mu\text{c}$ Due to a radioactive source, the plate loses charge at the rate of $1.8\times10^{-8}\frac{\text{C}}{\text{s}}$ The magnitude of displacement current is :
AnswerThe displacement current is that current which comes into play in the region in which the electric field and hence the electric flux is changing with time.
Maxwell found that conduction current $(I)$ and displacement current $(I_d)$ together have the property of continuity, although individually they may not be continuous.
Maxwell also predicted that this current produces the same magnetic field as a conduction current can produce.
Displacement current is given by
$\text{I}_\text{d}=\frac{\text{dq}}{\text{dt}}=1.8\times10^{-8}\frac{\text{C}}{\text{s}}$
View full question & answer→Question 1751 Mark
The concept of displacement current introduced by Maxwell removes asymmetry between.
Answer
- Faraday's law and Ampere' law
Explanation:
Maxwell added the concept of displacement current in AMpere Circuit Law which governs the conduction in the wire of conduction current. After the deviation compass between capacitor Maxwell thought of magnetic lines which would be the result of varying current known as displacement current. So by continuing the displacement in Amperes law, Maxwell was able to show the result of Amperes conduction in circuit moving electrons and also the result of faraday generation of ME waves.
View full question & answer→Question 1761 Mark
Consider the following two statements regarding a linearly polarised, plane electromagnetic wave:
- The electric field and the magnetic field have equal average values.
- The electric energy and the magnetic energy have equal average values.
AnswerFor a linearly polarised, plane electromagnetic wave,
$\text{E}=\text{E}_0\sin\omega\Big(\text{t}-\frac{\text{x}}{\text{c}}\Big)$
$\text{B}=\text{B}_0\sin\omega\Big(\text{t}-\frac{\text{x}}{\text{c}}\Big)$
The average value of either $E$ or Bover a cycle is zero $($average of $\sin(\theta)$ over a cycle is zero$)$.
Also the electric energy density $(U_E)$ and magnetic energy density $(U_B)$ are equal.
$\text{u}_\text{E}=\frac{1}{2}\in_0\text{E}^2=\frac{\text{B}^2}{2\mu_0}=\text{u}_\text{B}$
Energy can be found out by integrating energy density over the entire volume of full space.
As the energy of the electromagnetic wave is equally shared between electric and magnetic field so their average values will also be equal.
View full question & answer→Question 1771 Mark
Identify the electromagnetic wave which is also known as heatwaves.
Answer
- Infrared Waves
Explanation:
Infrared waves are heat radiations also known as heatwaves. These waves are produced by hot bodies and molecules. They do heating because water molecules present in most of the materials readily absorb infrared waves and their thermal motion increases, so they heat themselves and also heat their surroundings.
View full question & answer→Question 1781 Mark
Light wave is travelling along y - direction. If the corresponding E vector at any time along the x - axis, the direction of B vector at that time is along.

Answer
- z - axis
Explanation:
Light wave is an electromagnetic wave in which E and B are at right angles to each other as well as at right angles to the direction of wave propagation. So from the given information in the question, the direction of B vector is in positive z direction.
View full question & answer→MCQ 1791 Mark
The oscillating electric and magnetic vectors of an electromagnetic wave are oriented along
- A
The same direction but differ in phase by 90°
- B
The same direction and are in phase
- C
Mutually perpendicular directions and differ in phase by 90°
- ✓
Mutually perpendicular directions and are in phase
AnswerCorrect option: D. Mutually perpendicular directions and are in phase
View full question & answer→