MCQ
$\int_{ - 1}^1 {(\sqrt {1 + x + {x^2}} - \sqrt {1 - x + {x^2}} )\,dx} =$
- ✓$0$
- B$1$
- C$ - 1$
- Dએકપણ નહીં.
Then $f( - x) = \sqrt {1 - x + {x^2}} - \sqrt {1 + x + {x^2}} = - f(x)$
Hence $f(x)$ is an odd function and
so $\int_{ - 1}^1 {f(x)dx = 0} $.
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$STATEMENT -1$ : $\mathrm{P}\left(\mathrm{H}_{\mathrm{i}} \mid \mathrm{E}\right)>\mathrm{P}\left(\mathrm{E} \mid \mathrm{H}_{\mathrm{i}}\right) \cdot \mathrm{P}\left(\mathrm{H}_{\mathrm{i}}\right)$ for $\mathrm{i}=1,2, \ldots, \mathrm{n}$ because
$STATEMENT$ $-2: \sum_{1=1}^{\mathrm{n}} \mathrm{P}\left(\mathrm{H}_{\mathrm{i}}\right)=1$