MCQ
$\int_{}^{} {\frac{1}{{{{\cos }^2}x{{(1 - \tan x)}^2}}}dx = } $
- A$\frac{1}{{\tan x - 1}} + c$
- ✓$\frac{1}{{1 - \tan x}} + c$
- C$ - \frac{1}{3}\frac{1}{{{{(1 - \tan x)}^3}}} + c$
- Dએકપણ નહિ.
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