MCQ
$\int {\frac{{{e^{{{\tan }^{ - 1}}\sqrt x }}}}{{\sqrt x + x\sqrt x }}dx = } $
- A${e^{{{\tan }^{ - 1}}\sqrt x }} + c$
- B$\frac{1}{2}{e^{{{\tan }^{ - 1}}\sqrt x }} + c$
- C$\log {\tan ^{ - 1}}\sqrt x + c$
- D$2{e^{{{\tan }^{ - 1}}\sqrt x }} + c$
$\frac{1}{1+x} \times \frac{1}{2 \sqrt{x}} d x=d t$
$\frac{d x}{\sqrt{x}+x \sqrt{x}}=2 d t$
$\int \mathrm{e}^{\mathrm{t}} 2 \mathrm{dt}=2 \mathrm{e}^{\mathrm{t}}+\mathrm{c}$
$=2 \mathrm{e}^{\tan ^{-1} \sqrt{\mathrm{x}}}+\mathrm{c}$
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