MCQ
$\int_0^1 {\sqrt {\frac{{1 - x}}{{1 + x}}} } \,dx =$
- ✓$\left( {\frac{\pi }{2} - 1} \right)$
- B$\left( {\frac{\pi }{2} + 1} \right)$
- C$\frac{\pi }{2}$
- D$(\pi + 1)$
$ = \int_0^1 {\frac{{1 - x}}{{\sqrt {1 - {x^2}} }}dx = \int_0^1 {\frac{{dx}}{{\sqrt {1 - {x^2}} }}} - \int_0^1 {\frac{x}{{\sqrt {1 - {x^2}} }}\,} dx} $
$I = [{\sin ^{ - 1}}x]_0^1 + [\sqrt {1 - {x^2}} ]_0^1 = \frac{\pi }{2} - 1$.
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