$CH _{4}+2 O _{2} \rightarrow CO _{2}+2 H _{2} O (\Delta H =-891 kJ / mol)$
$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$
$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$
$C$(ગ્રેફાઈટ) $+$ $\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ પ્રક્રિયા માટે $\Delta H ^\theta$ શોધો.
$\Delta H \,(kJ/mol)$ | |
$\frac 12 A \rightarrow B$ | $+150$ |
$3B \rightarrow 2C + D$ | $-125$ |
$E + A \rightarrow 2D$ | $+350$ |