\(\xrightarrow{{{C}_{2}}{{H}_{5}}Cl}{{({{C}_{2}}{{H}_{5}})}_{3}}N\xrightarrow{{{C}_{2}}{{H}_{5}}Cl}\) \(\underset{\text{Tetraethyl}\text{ammonium}\text{chloride}}{\mathop{{{\left[ \begin{matrix}
\begin{matrix}
\,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}} \\
| \\
\end{matrix} \\
{{C}_{2}}{{H}_{5}}-N-{{C}_{2}}{{H}_{5}} \\
| \\
\,\,\,\,\,\,\,\,{{C}_{2}}{{H}_{5}} \\
\end{matrix} \right]}^{+}}}}\,C{{l}^{-}}\)
If \(N{H_3}\) is in excess, then \({1^o}\) amine will be the main product, if \({C_2}{H_5}Cl\) is in excess then mixture of \({1^o},{2^o},{3^o}\) and quaternary amine is obtained.
$(I)\,\begin{array}{*{20}{c}}
{C{H_3}CHC{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl\,\,\,\,\,\,\,\,\,}
\end{array}$
$(II)\,CH_3CH_2CH_2Cl$
$(III)\,H_3CO-C_6H_4-CH_2Cl$