Mass of silver left = $ 0.162 \,gm$

Basicity of acid = $2$

Step $1 -$ To calculate the equivalent mass of the silver salt $(E)$

$\frac{{{\rm{Eq}}{\rm{.}}\,\,{\rm{mass}}\,\,{\rm{of}}\,\,{\rm{silver}}\,\,{\rm{salt}}}}{{{\rm{Eq}}{\rm{.}}\,\,{\rm{mass}}\,\,{\rm{of}}\,\,{\rm{silver}}}} = \frac{{{\rm{Mass}}\,\,{\rm{of}}\,\,{\rm{Acid}}\,\,{\rm{taken}}}}{{{\rm{Mass}}\,\,{\rm{of}}\,\,{\rm{silver}}\,\,{\rm{left}}}}$

$ \frac{E}{{108}} = \frac{{0.228}}{{0.162}}$

$ E = \frac{{0.228}}{{0.162}} \times 108 = 152\,({\rm{Eq}}{\rm{.}}\,\,{\rm{mass}}\,\,{\rm{of}}\,\,{\rm{silver}}\,\,{\rm{salt)}}$

Step $2$ -To calculate the eq. mass of acid.

Eq. mass of acid = Eq. mass of silver salt -Eq. mass of $Ag$ + Basicity

= $152 -108 + 1 = 152 -109 = 43$ (Eq. mass of acid)

Step $3 -$ To determine the molecular mass of acid.

Mol. mass of the acid = Eq. mass of acid $\times$ basicity = $45 \times 2 = 90$