\(4 gm\) \( H_2\) \( \rightarrow\) \( u2 = 2\) મોલ
\(8 gm\) \( He \) \( \rightarrow \) \(m3 = 2\) મોલ
\(M\) કુલ = \(28 + 4 + 8 = 40 gm\)
\({\rho _{mix}} = \frac{{M\,total}}{V}\,\,\,\, \Rightarrow \,\,\,V = \frac{{nRT}}{P} = \frac{{5 \times 8.3 \times 400}}{{8.3 \times {{10}^5}}} = 2 \times {10^{ - 2}}{m^3}\)
\({\rho _{mix}} = \frac{{40}}{{2 \times {{10}^2}}} = 2000\,\,gm/{m^3} = 2\,gm\)\(/\)લિટર .