\(s\) \(s\) \(s\)
\(NaCl ⇌ Na^+ + Cl^-\)
\(0.001\) \( 0.001\) \(0.001 \)
આથી, [\(Ag^+] = s\) \([Cl^-] = s + 0.001\)
\(K_{sp} = [Ag^+]\) \([Cl^-]\)
\((s)\) \((s + 0.001) = s^2 + 0.001s = 10^{-10}\)
\(s^2 <<< 1\)
\(\therefore \,\,0.001\, = {10^{ - 10}}\,\,\,\,\,s = \frac{{{{10}^{ - 10}}}}{{{{10}^{ - 3}}}} = {10^{ - 7}}\)
($PbCl_2$ નો $K_{SP}$ $ = 3.2 \times 10^{-8}$; $Pb$ નું પરમાણ્વીય દળ $= 207\, u$)