$K_{sp}$ $=$ $[M^{+3}] [OH^-]^3 $=$ s(3s)^3$
$⇒$ $27s^4 $= $27 \times10^{-12}$
$s = 10^{-3} [OH^{-1}] = 3s = 3 \times 10^{-3}$
$(K_w = 10^{-14})$
|
ક્રમ |
સૂત્ર |
દ્રવ્યતા ગુણાકાર |
|
$1$ |
$PQ$ |
$4.0\times 10^{-20}$ |
|
$2$ |
$PQ_2$ |
$3.2 \times 10^{-14}$ |
|
$3$ |
$PQ_3$ |
$2.7\times 10^{-35}$ |