MCQ
જો $\cos A = \frac{3}{4}$, તો $32\sin \frac{A}{2}\cos \frac{5}{2}A = $
- A$\sqrt 7 $
- ✓$ - \sqrt 7 $
- C$7$
- D$-7$
$L.H.S.$ $ = 16(\sin 3A - \sin 2A)$
$ = 16\sin A(3 - 4{\sin ^2}A - 2\cos A)$
$ = 16.\frac{{\sqrt 7 }}{4}\left( {3 - 4.\frac{7}{{16}} - 2.\frac{3}{4}} \right) = - \sqrt 7 $.
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