MCQ
જો $f(x) = \left\{ {\begin{array}{*{20}{c}}
{\,{x^3} - {x^2} + 10x - 5\,\,,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x \le 1\,\,\,\,\,\,\,\,\,\,\,\,}\\
{ - 2x + {{\log }_2}({b^2} - 2),\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\, > 1\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \right.$ હોય તો $b$ ની કઇ કિમતો માટે $f(x)$ ની $x = 1$ મહત્તમ કિમત મળે
{\,{x^3} - {x^2} + 10x - 5\,\,,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x \le 1\,\,\,\,\,\,\,\,\,\,\,\,}\\
{ - 2x + {{\log }_2}({b^2} - 2),\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\, > 1\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \right.$ હોય તો $b$ ની કઇ કિમતો માટે $f(x)$ ની $x = 1$ મહત્તમ કિમત મળે
- A$1 \le b \le 2$
- B$b = \{ 1,2\} $
- C$b \in ( - \infty , - 1)$
- D$\left[ { - \sqrt {130} , - \sqrt 2 } \right) \cup \left( {\sqrt 2 ,\sqrt {130} } \right]$