MCQ
જો $F(x) = \int_{{x^2}}^{{x^3}} {\log t\,dt,\,\,(x > 0),} $ તો $F'(x) = $
- ✓$(9{x^2} - 4x)\log x$
- B$(4x - 9{x^2})\log x$
- C$(9{x^2} + 4x)\log x$
- Dએકપણ નહીં.
Applying Leibnitzaes theorem,
$F\,'(x) = \log {x^3}.\frac{d}{{dx}}{x^3} - \log {x^2}.\frac{d}{{dx}}{x^2}$
$ = 3\log x \cdot 3{x^2} - 2\log x \cdot 2x$
$ = (9{x^2} - 4x)\log x$.
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